Question

Hofmann Bromamide degradation is given by:
A. Imide
B. Acid chloride
C. Acid anhydride
D. Amide

Answer 1

Hint: It is known to us that Hofmann Bromamide degradation reaction is used for the formation of primary amine. In this reaction, the group which is also called a peptide bond reacts with bromine under the action of sodium hydroxide.

Complete step by step answer:
We know that, a chemical bond which is formed between carboxylic group \[\left( { - {\rm{COOH}}} \right)\]of one amino acid and amino group\[\left( { - {\rm{N}}{{\rm{H}}_{\rm{2}}}} \right)\] of the other amino acid, which results in the formation of \[\left( {{\rm{CO - NH}}} \right)\]bond, it is known as a peptide bond. . Thus, the peptide bond is also called an amide group.
Now, let’s discuss what basically the Hofmann Bromamide degradation reaction is.
It is the reaction of an amide with ${\rm{B}}{{\rm{r}}_{\rm{2}}}$ in the presence of ${\rm{NaOH}}$ to give primary amine. The degradation of amide occurs in this reaction that leads to the formation of primary amine. The resulting primary amine has one carbon atom less as compared to the number of carbon atoms which are present in amide. The general Hofmann Bromamide degradation is shown below.
${\rm{RCON}}{{\rm{H}}_2} + {\rm{B}}{{\rm{r}}_2} + 4{\rm{NaOH}} \to {\rm{R - N}}{{\rm{H}}_2} + {\rm{N}}{{\rm{a}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_3} + 2{\rm{NaBr}} + 2{{\rm{H}}_{\rm{2}}}{\rm{O}}$
Here, R represents an alkyl or aryl group.
Hence, we can say that Hofmann Bromamide degradation is given by amide.

Hence, the correct option is (D).

Note:
Some important applications of Hofmann Bromamide degradation are stated below.
We found that this reaction is useful in the conversion of aliphatic or aromatic amides into aliphatic or aromatic amines.
It is also useful in the preparation of anthranilic acid by using phthalimide.