
Heating of \[MgC{l_2}.6{H_2}O\] gives anhydrous \[MgC{l_2}\] . If true enters 1, else enter 0.
Answer
567.9k+ views
Hint: \[MgC{l_2}.6{H_2}O\]on heating will give \[MgC{l_2}\] and \[6{H_2}O\] and it means that \[MgC{l_2}\] is available in anhydrous form. \[MgC{l_2}.6{H_2}O\] removes water.
Complete step wise step answer:
\[MgC{l_2}.6{H_2}O\] undergoes partial hydrolysis on its own water molecules of crystallization when it is heated. \[MgC{l_2}.6{H_2}O\] upon heating gives \[MgC{l_2}.2{H_2}O\] and then \[Mg\left( {OH} \right)Cl\] or \[MgOCl{\text{ }} + {\text{ }}HCl\] which it is strongly heated gives MgO. When \[MgC{l_2}\] is strongly heated, then it forms MgO.
On heating, \[MgC{l_2}.6{H_2}O\] readily loses 4 molecules of water of crystallization to form $MgC{l_2}$. Upon heating, \[MgC{l_2}.6{H_2}O\] went upon the processes of dehydration and hydrolysis simultaneously accompanied by the release of HCl between \[{150^0}C\] and \[500^\circ C\]. The remaining two molecules of water are not removed but react chemically with \[MgC{l_2}\] to form MgO. The thermal decomposition mechanisms and the intermediate morphology of \[MgC{l_2}.6{H_2}O\] and \[MgC{l_2}.{H_2}O\] were observed using integrated thermal analysis, X-ray diffraction, scanning electron microscope and chemical analysis.
This results showed that there was six steps in the thermal decomposition of \[MgC{l_2}.6{H_2}O\]: producing \[MgC{l_2}.4{H_2}O\] at \[69^\circ C\], \[MgC{l_2}.2{H_2}O\] at \[129^\circ C\], \[MgC{l_2}.{H_2}O\] \[\left( {1 \leqslant n \leqslant 2} \right)\] and \[Mg(OH)Cl\] at \[167^\circ C\] ,
the conversion of \[MgC{l_2}.{H_2}O\] \[\left( {1 \leqslant n \leqslant 2} \right)\] to \[Mg(OH)Cl.3{H_2}O\] by continuous dehydration and hydrolysis at \[203^\circ C\], the dehydration of \[Mg(OH)Cl.3{H_2}O\] to \[Mg(OH)Cl\] at \[235^\circ C\] , and hence the direct conversion of \[Mg(OH)Cl\] to the cylindrical particles of MgO at \[415^\circ C\].
So, It's true that \[MgC{l_2}.6{H_2}O\] on heating gives anhydrous \[MgC{l_2}\] ,
so we enter 1.
Note: \[MgC{l_2}.6{H_2}O\] went through the processes of dehydration and hydrolysis simultaneously accompanied by the release of HCl between \[{150^0}C\] and \[500^\circ C\]. At a temperature higher than \[500^\circ C\], \[Mg\left( {OH} \right)Cl\] gradually releases part of HCl.
Complete step wise step answer:
\[MgC{l_2}.6{H_2}O\] undergoes partial hydrolysis on its own water molecules of crystallization when it is heated. \[MgC{l_2}.6{H_2}O\] upon heating gives \[MgC{l_2}.2{H_2}O\] and then \[Mg\left( {OH} \right)Cl\] or \[MgOCl{\text{ }} + {\text{ }}HCl\] which it is strongly heated gives MgO. When \[MgC{l_2}\] is strongly heated, then it forms MgO.
On heating, \[MgC{l_2}.6{H_2}O\] readily loses 4 molecules of water of crystallization to form $MgC{l_2}$. Upon heating, \[MgC{l_2}.6{H_2}O\] went upon the processes of dehydration and hydrolysis simultaneously accompanied by the release of HCl between \[{150^0}C\] and \[500^\circ C\]. The remaining two molecules of water are not removed but react chemically with \[MgC{l_2}\] to form MgO. The thermal decomposition mechanisms and the intermediate morphology of \[MgC{l_2}.6{H_2}O\] and \[MgC{l_2}.{H_2}O\] were observed using integrated thermal analysis, X-ray diffraction, scanning electron microscope and chemical analysis.
This results showed that there was six steps in the thermal decomposition of \[MgC{l_2}.6{H_2}O\]: producing \[MgC{l_2}.4{H_2}O\] at \[69^\circ C\], \[MgC{l_2}.2{H_2}O\] at \[129^\circ C\], \[MgC{l_2}.{H_2}O\] \[\left( {1 \leqslant n \leqslant 2} \right)\] and \[Mg(OH)Cl\] at \[167^\circ C\] ,
the conversion of \[MgC{l_2}.{H_2}O\] \[\left( {1 \leqslant n \leqslant 2} \right)\] to \[Mg(OH)Cl.3{H_2}O\] by continuous dehydration and hydrolysis at \[203^\circ C\], the dehydration of \[Mg(OH)Cl.3{H_2}O\] to \[Mg(OH)Cl\] at \[235^\circ C\] , and hence the direct conversion of \[Mg(OH)Cl\] to the cylindrical particles of MgO at \[415^\circ C\].
So, It's true that \[MgC{l_2}.6{H_2}O\] on heating gives anhydrous \[MgC{l_2}\] ,
so we enter 1.
Note: \[MgC{l_2}.6{H_2}O\] went through the processes of dehydration and hydrolysis simultaneously accompanied by the release of HCl between \[{150^0}C\] and \[500^\circ C\]. At a temperature higher than \[500^\circ C\], \[Mg\left( {OH} \right)Cl\] gradually releases part of HCl.
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