
How much heat is absorbed by a \[2000\text{ }kg\] granite boulder as energy from sun causes its temperature to change from \[10{}^\circ C\text{ }to\text{ }29{}^\circ C\] ?
Answer
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Hint: We know that the specific heat capacity of substance which is defined as heat energy required to raise temperature or as we can have unit mass of substance by \[1{}^\circ C\] The term was initially define such that specific heat capacity of a water would be given as L this resulted in unit of energy called as calories.
Complete step-by-step answer:The term specific heat capacity is define to determine the amount of a heat required to raise temperature of unit mass of water by \[1{}^\circ C\] Since water is most commonly use liquid in a calorimeter thus a new unit of energy is defined it's called calories.
A calorie is defined as amount of a heat required to raise temperature of a $1$ gram of the water by
\[1{}^\circ C\] According to specific heat capacity of water is \[1\text{ }\dfrac{cal}{g\cdot {}^\circ C}\]
The dimensions units which we use in value and units given in questions are different.
Heat absorbed is given by
\[H\text{ }=\text{ }m\cdot c\cdot \partial \left( \theta \right)\text{ }\ldots \ldots \ldots \ldots \ldots \ldots ..\left( 1 \right)\]
here \[m\text{ }=\] mass along with \[c\text{ }=\] specific heat capacity
Assuming \[c\text{ }=\text{ }790\text{ }\dfrac{J}{kg}/K\] for granite
Here, ∂(theta) is the change in temperature
\[\partial \left( \theta \right)\text{ }=\text{ }29\text{ }-\text{ }10\text{ }=\text{ }19K\]
Therefore now re-substituting values in equation of heat absorbed that is \[\left( 1 \right),\]
\[H\text{ }=\text{ }2000\text{ }\times \text{ }790\text{ }\times \text{ }19\]
\[H\text{ }=\text{ }3002000\text{ }J\]
\[H\text{ }=\text{ }3.002\text{ }MJ\]
Therefore, \[3.002\text{ }MJ\] amount of heat is absorbed by a \[2000\text{ }kg\] granite boulder as a energy from sun causes its temperature to change from \[10{}^\circ C\text{ }to\text{ }29{}^\circ C\]
Note: Note that the term calories is defined specifically keeping property of a water, therefore most of the time value corresponding to water in a calorie is unity. The joule on the other hand is derived from other metric units as well as it has to be equated with calories to find equivalent value.
Complete step-by-step answer:The term specific heat capacity is define to determine the amount of a heat required to raise temperature of unit mass of water by \[1{}^\circ C\] Since water is most commonly use liquid in a calorimeter thus a new unit of energy is defined it's called calories.
A calorie is defined as amount of a heat required to raise temperature of a $1$ gram of the water by
\[1{}^\circ C\] According to specific heat capacity of water is \[1\text{ }\dfrac{cal}{g\cdot {}^\circ C}\]
The dimensions units which we use in value and units given in questions are different.
Heat absorbed is given by
\[H\text{ }=\text{ }m\cdot c\cdot \partial \left( \theta \right)\text{ }\ldots \ldots \ldots \ldots \ldots \ldots ..\left( 1 \right)\]
here \[m\text{ }=\] mass along with \[c\text{ }=\] specific heat capacity
Assuming \[c\text{ }=\text{ }790\text{ }\dfrac{J}{kg}/K\] for granite
Here, ∂(theta) is the change in temperature
\[\partial \left( \theta \right)\text{ }=\text{ }29\text{ }-\text{ }10\text{ }=\text{ }19K\]
Therefore now re-substituting values in equation of heat absorbed that is \[\left( 1 \right),\]
\[H\text{ }=\text{ }2000\text{ }\times \text{ }790\text{ }\times \text{ }19\]
\[H\text{ }=\text{ }3002000\text{ }J\]
\[H\text{ }=\text{ }3.002\text{ }MJ\]
Therefore, \[3.002\text{ }MJ\] amount of heat is absorbed by a \[2000\text{ }kg\] granite boulder as a energy from sun causes its temperature to change from \[10{}^\circ C\text{ }to\text{ }29{}^\circ C\]
Note: Note that the term calories is defined specifically keeping property of a water, therefore most of the time value corresponding to water in a calorie is unity. The joule on the other hand is derived from other metric units as well as it has to be equated with calories to find equivalent value.
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