
What happens when?
$(i)$ Magnesium is burnt in air
$(ii)$ Quick lime is heated with silica
$(iii)$ Chlorine react with slaked lime
$(iv)$ Calcium nitrate is heated
Answer
611.7k+ views
Hint – In this question the concept that burnt air means that we are reacting the compound with oxygen (O2) and nitrogen (N2) present in the air. CaO is the chemical formula for quick lime and silica is (SiO2). The chemical formula for slaked lime is $Ca{(OH)_2}$. Calcium nitrate is $Ca{(N{O_3})_2}$. Use them to formulate the chemical reactions to get the products.
Complete answer:
$\left( i \right)$ When magnesium (MgO) is burnt in air it reacts with oxygen (O2) and nitrogen (N2)present in the air and forms a magnesium oxide (MgO) and magnesium nitride (Mg3N2) , the chemical reaction is given below,
\[ \Rightarrow 5Mg + {O_2} + {N_2}\xrightarrow{{{\text{burnt}}}}2MgO + M{g_3}{N_2}\]
$\left( {ii} \right)$ When quick lime (CaO) is heated with silica (SiO2) calcium silicate (CaSiO3) is formed, the chemical reaction is given below,
\[ \Rightarrow CaO + Si{O_2}\xrightarrow{{{\text{heated}}}}CaSi{O_3}\]
$\left( {iii} \right)$ When chlorine (Cl) reacts with slaked lime Ca (OH)2 calcium hypochlorite $\left[ {CaC{l_2} + Ca{{\left( {OCl} \right)}_2}} \right]$ is formed which is a constituent of a bleaching powder, the chemical reaction is given below,
$ \Rightarrow 2Ca{\left( {OH} \right)_2} + 2C{l_2}\xrightarrow{{}}CaC{l_2} + Ca{\left( {OCl} \right)_2} + 2{H_2}O$
$\left( {iv} \right)$ When calcium nitrate Ca(NO3)2 is heated calcium oxide (CaO), nitrogen-dioxide (NO2) and oxygen is released, the chemical reaction is given below,
$ \Rightarrow 2Ca{\left( {N{O_3}} \right)_2}\xrightarrow{{{\text{heated}}}}2CaO + 4N{O_2} + {O_2}$
So this is the required answer.
Note – The concerning point is regarding the by-product formulation of chemical equations on reacting reactants always form the main product along with the by-products just like in chemical reaction $2Ca{\left( {OH} \right)_2} + 2C{l_2}\xrightarrow{{}}CaC{l_2} + Ca{\left( {OCl} \right)_2} + 2{H_2}O$, bleaching powder is formed however water is also formed as the by-product. Equation balancing is very important. The key logic behind it is that the number of atoms for each element in the reaction and the total charge is the same both the reactants that are on the left side of the equation and the products that are on the right side of the equation.
Complete answer:
$\left( i \right)$ When magnesium (MgO) is burnt in air it reacts with oxygen (O2) and nitrogen (N2)present in the air and forms a magnesium oxide (MgO) and magnesium nitride (Mg3N2) , the chemical reaction is given below,
\[ \Rightarrow 5Mg + {O_2} + {N_2}\xrightarrow{{{\text{burnt}}}}2MgO + M{g_3}{N_2}\]
$\left( {ii} \right)$ When quick lime (CaO) is heated with silica (SiO2) calcium silicate (CaSiO3) is formed, the chemical reaction is given below,
\[ \Rightarrow CaO + Si{O_2}\xrightarrow{{{\text{heated}}}}CaSi{O_3}\]
$\left( {iii} \right)$ When chlorine (Cl) reacts with slaked lime Ca (OH)2 calcium hypochlorite $\left[ {CaC{l_2} + Ca{{\left( {OCl} \right)}_2}} \right]$ is formed which is a constituent of a bleaching powder, the chemical reaction is given below,
$ \Rightarrow 2Ca{\left( {OH} \right)_2} + 2C{l_2}\xrightarrow{{}}CaC{l_2} + Ca{\left( {OCl} \right)_2} + 2{H_2}O$
$\left( {iv} \right)$ When calcium nitrate Ca(NO3)2 is heated calcium oxide (CaO), nitrogen-dioxide (NO2) and oxygen is released, the chemical reaction is given below,
$ \Rightarrow 2Ca{\left( {N{O_3}} \right)_2}\xrightarrow{{{\text{heated}}}}2CaO + 4N{O_2} + {O_2}$
So this is the required answer.
Note – The concerning point is regarding the by-product formulation of chemical equations on reacting reactants always form the main product along with the by-products just like in chemical reaction $2Ca{\left( {OH} \right)_2} + 2C{l_2}\xrightarrow{{}}CaC{l_2} + Ca{\left( {OCl} \right)_2} + 2{H_2}O$, bleaching powder is formed however water is also formed as the by-product. Equation balancing is very important. The key logic behind it is that the number of atoms for each element in the reaction and the total charge is the same both the reactants that are on the left side of the equation and the products that are on the right side of the equation.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
What is the median of the first 10 natural numbers class 10 maths CBSE

Which women's tennis player has 24 Grand Slam singles titles?

Who is the Brand Ambassador of Incredible India?

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

A moving boat is observed from the top of a 150 m high class 10 maths CBSE

