How do you graph \[y=\arccos \left( \dfrac{x}{3} \right)\]?
Answer
609.3k+ views
Hint: In order to find the graph of the given equation in the question that is \[y=\arccos \left( \dfrac{x}{3} \right)\], find the points that satisfy this equation and then plot them in the graph.
Complete step by step solution:
Given equation in the question is as follows
\[y=\arccos \left( \dfrac{x}{3} \right)\]
Consider the above equation as the function\[f\left( x \right)=\arccos \left( \dfrac{x}{3} \right)\]
To find the points that satisfy this equation first consider the point at \[x=-3\]
Replace the variable \[x\] with \[-3\] in the expression, we get:
\[\Rightarrow f\left( -3 \right)=\arccos \left( \dfrac{-3}{3} \right)=\pi \]
\[\Rightarrow f\left( -3 \right)=\pi \]
Now consider the point at \[x=\dfrac{-3}{2}\]
Replace the variable \[x\] with \[\dfrac{-3}{2}\]in the expression, we get:
\[\Rightarrow f\left( \dfrac{-3}{2} \right)=\arccos \left( \dfrac{-\dfrac{3}{2}}{3} \right)\]
Simplify it further and multiply the numerator by the reciprocal of the denominator.
\[\Rightarrow f\left( \dfrac{-3}{2} \right)=\arccos \left( -\dfrac{3}{2}\cdot \dfrac{1}{3} \right)\]
Cancel the common factor of \[3\] to do this follow the following steps:
Move the leading negative in \[\dfrac{-3}{2}\]into the numerator.
\[\Rightarrow f\left( \dfrac{-3}{2} \right)=\arccos \left( -\dfrac{3}{2}\cdot \dfrac{1}{3} \right)\]
Factor \[3\] out of \[-3\].
\[\Rightarrow f\left( -\dfrac{3}{2} \right)=\arccos \left( \dfrac{3\left( -1 \right)}{2}\cdot \dfrac{1}{3} \right)\]
Cancel the common factor.
\[\Rightarrow f\left( -\dfrac{3}{2} \right)=\arccos \left( \dfrac{{3}\cdot -1}{2}\cdot \dfrac{1}{{{3}}} \right)\]
Rewrite the expression, we get:
\[\Rightarrow f\left( -\dfrac{3}{2} \right)=\arccos \left( \dfrac{-1}{2} \right)\]
Move the negative in front of the fraction.
\[\Rightarrow f\left( -\dfrac{3}{2} \right)=\arccos \left( -\dfrac{1}{2} \right)\]
The exact value of \[\arccos \left( -\dfrac{1}{2} \right)\] is \[\dfrac{2\pi }{3}\].
\[\Rightarrow f\left( -\dfrac{3}{2} \right)=\dfrac{2\pi }{3}\]
After this consider the point at \[x=0\]
Replace the variable \[x\] with \[0\] in the expression, we get:
\[\Rightarrow f\left( 0 \right)=\arccos \left( \dfrac{0}{3} \right)\]
Simplify it further and divide \[0\] by \[3\], we get:
\[\Rightarrow f\left( 0 \right)=\arccos \left( 0 \right)\]
The exact value of \[\arccos \left( 0 \right)\] is \[\dfrac{\pi }{2}\].
\[\Rightarrow f\left( 0 \right)=\dfrac{\pi }{2}\]
Now find for the point at \[x=\dfrac{3}{2}\].
Replace the variable \[x\] with \[\dfrac{3}{2}\] in the expression, we get:
\[\Rightarrow f\left( \dfrac{3}{2} \right)=\arccos \left( \dfrac{\dfrac{3}{2}}{3} \right)\]
Simplify it further and multiply the numerator by the reciprocal of the denominator.
\[\Rightarrow f\left( \dfrac{3}{2} \right)=\arccos \left( \dfrac{3}{2}\cdot \dfrac{1}{3} \right)\]
Cancel the common factor of \[3\], we get
\[\Rightarrow f\left( \dfrac{3}{2} \right)=\arccos \left( \dfrac{1}{2} \right)\]
The exact value of \[\arccos \left( \dfrac{1}{2} \right)\]is \[\dfrac{\pi }{3}\].
\[\Rightarrow f\left( \dfrac{3}{2} \right)=\dfrac{\pi }{3}\]
Now at last find the point at \[x=3\]
Replace the variable \[x\]with \[3\] in the expression, we get:
\[\Rightarrow f\left( 3 \right)=\arccos \left( \dfrac{3}{3} \right)\]
Simplify it further and divide \[3\] by \[3\], we get:
\[\Rightarrow f\left( 3 \right)=\arccos \left( 1 \right)\]
The exact value of \[\arccos \left( 1 \right)\]is \[0\].
\[\Rightarrow f\left( 3 \right)=0\]
Now list all the points in a table and this trigonometric function can be graphed by plotting these points.
\[\begin{matrix}
x & f\left( x \right) \\
-3 & \pi \\
-\dfrac{3}{2} & \dfrac{2\pi }{3} \\
0 & \dfrac{\pi }{2} \\
\dfrac{3}{2} & \dfrac{\pi }{3} \\
3 & 0 \\
\end{matrix}\]
The graph of the function \[f\left( x \right)=\arccos \left( \dfrac{x}{3} \right)\] is as follows:
Note: Students generally make calculation mistakes while calculating the points that satisfy the graph. It's important to remember the trigonometric values and recheck the calculations once done.
Complete step by step solution:
Given equation in the question is as follows
\[y=\arccos \left( \dfrac{x}{3} \right)\]
Consider the above equation as the function\[f\left( x \right)=\arccos \left( \dfrac{x}{3} \right)\]
To find the points that satisfy this equation first consider the point at \[x=-3\]
Replace the variable \[x\] with \[-3\] in the expression, we get:
\[\Rightarrow f\left( -3 \right)=\arccos \left( \dfrac{-3}{3} \right)=\pi \]
\[\Rightarrow f\left( -3 \right)=\pi \]
Now consider the point at \[x=\dfrac{-3}{2}\]
Replace the variable \[x\] with \[\dfrac{-3}{2}\]in the expression, we get:
\[\Rightarrow f\left( \dfrac{-3}{2} \right)=\arccos \left( \dfrac{-\dfrac{3}{2}}{3} \right)\]
Simplify it further and multiply the numerator by the reciprocal of the denominator.
\[\Rightarrow f\left( \dfrac{-3}{2} \right)=\arccos \left( -\dfrac{3}{2}\cdot \dfrac{1}{3} \right)\]
Cancel the common factor of \[3\] to do this follow the following steps:
Move the leading negative in \[\dfrac{-3}{2}\]into the numerator.
\[\Rightarrow f\left( \dfrac{-3}{2} \right)=\arccos \left( -\dfrac{3}{2}\cdot \dfrac{1}{3} \right)\]
Factor \[3\] out of \[-3\].
\[\Rightarrow f\left( -\dfrac{3}{2} \right)=\arccos \left( \dfrac{3\left( -1 \right)}{2}\cdot \dfrac{1}{3} \right)\]
Cancel the common factor.
\[\Rightarrow f\left( -\dfrac{3}{2} \right)=\arccos \left( \dfrac{{3}\cdot -1}{2}\cdot \dfrac{1}{{{3}}} \right)\]
Rewrite the expression, we get:
\[\Rightarrow f\left( -\dfrac{3}{2} \right)=\arccos \left( \dfrac{-1}{2} \right)\]
Move the negative in front of the fraction.
\[\Rightarrow f\left( -\dfrac{3}{2} \right)=\arccos \left( -\dfrac{1}{2} \right)\]
The exact value of \[\arccos \left( -\dfrac{1}{2} \right)\] is \[\dfrac{2\pi }{3}\].
\[\Rightarrow f\left( -\dfrac{3}{2} \right)=\dfrac{2\pi }{3}\]
After this consider the point at \[x=0\]
Replace the variable \[x\] with \[0\] in the expression, we get:
\[\Rightarrow f\left( 0 \right)=\arccos \left( \dfrac{0}{3} \right)\]
Simplify it further and divide \[0\] by \[3\], we get:
\[\Rightarrow f\left( 0 \right)=\arccos \left( 0 \right)\]
The exact value of \[\arccos \left( 0 \right)\] is \[\dfrac{\pi }{2}\].
\[\Rightarrow f\left( 0 \right)=\dfrac{\pi }{2}\]
Now find for the point at \[x=\dfrac{3}{2}\].
Replace the variable \[x\] with \[\dfrac{3}{2}\] in the expression, we get:
\[\Rightarrow f\left( \dfrac{3}{2} \right)=\arccos \left( \dfrac{\dfrac{3}{2}}{3} \right)\]
Simplify it further and multiply the numerator by the reciprocal of the denominator.
\[\Rightarrow f\left( \dfrac{3}{2} \right)=\arccos \left( \dfrac{3}{2}\cdot \dfrac{1}{3} \right)\]
Cancel the common factor of \[3\], we get
\[\Rightarrow f\left( \dfrac{3}{2} \right)=\arccos \left( \dfrac{1}{2} \right)\]
The exact value of \[\arccos \left( \dfrac{1}{2} \right)\]is \[\dfrac{\pi }{3}\].
\[\Rightarrow f\left( \dfrac{3}{2} \right)=\dfrac{\pi }{3}\]
Now at last find the point at \[x=3\]
Replace the variable \[x\]with \[3\] in the expression, we get:
\[\Rightarrow f\left( 3 \right)=\arccos \left( \dfrac{3}{3} \right)\]
Simplify it further and divide \[3\] by \[3\], we get:
\[\Rightarrow f\left( 3 \right)=\arccos \left( 1 \right)\]
The exact value of \[\arccos \left( 1 \right)\]is \[0\].
\[\Rightarrow f\left( 3 \right)=0\]
Now list all the points in a table and this trigonometric function can be graphed by plotting these points.
\[\begin{matrix}
x & f\left( x \right) \\
-3 & \pi \\
-\dfrac{3}{2} & \dfrac{2\pi }{3} \\
0 & \dfrac{\pi }{2} \\
\dfrac{3}{2} & \dfrac{\pi }{3} \\
3 & 0 \\
\end{matrix}\]
The graph of the function \[f\left( x \right)=\arccos \left( \dfrac{x}{3} \right)\] is as follows:
Note: Students generally make calculation mistakes while calculating the points that satisfy the graph. It's important to remember the trigonometric values and recheck the calculations once done.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

How many kilometers are there in 100 meters class 11 maths CBSE

