
How do you graph $ y = - \tan \left( {2x} \right) $ and include two full periods ?
Answer
523.5k+ views
Hint: A graph of a function f is the set of ordered pairs; the equation of graph is generally represented as $ y = f\left( x \right) $ , where x and $ f\left( x \right) $ are real numbers. We substitute the value of x and we determine the value of y and then we mark the points in the graph and we join the points.
Complete step-by-step answer:
Here, in the given question, we have to plot the graph for the given function. A graph of a function is a set of ordered pairs and it is represented as $ y = f\left( x \right) $ , where x and $ f\left( x \right) $ are real numbers. These pairs are in the form of cartesian form and the graph is the two-dimensional graph.
First, we have to find the value of y by using the graph equation $ y = - \tan \left( {2x} \right) $ .
Let us substitute the value of x as $ \dfrac{\pi }{2} $ .
$ \Rightarrow y = - \tan \left( {2 \times \dfrac{\pi }{2}} \right) = - \tan \left( \pi \right) $
$ \Rightarrow y = 0 $
Let us substitute the value of x as $ 0 $ .
$ \Rightarrow y = - \tan \left( {2 \times 0} \right) = - \tan \left( 0 \right) $
$ \Rightarrow y = 0 $
Now we consider the value of x as $ \dfrac{\pi }{6} $ , the value of y is
$ \Rightarrow y = - \tan \left( {2 \times \dfrac{\pi }{6}} \right) = - \tan \left( {\dfrac{\pi }{3}} \right) $
$ \Rightarrow y = - \sqrt 3 $
Now we consider the value of x as $ \left( {\dfrac{\pi }{3}} \right) $ , the value of y is
$ \Rightarrow y = - \tan \left( {2 \times \dfrac{\pi }{3}} \right) = - \tan \left( {\dfrac{{2\pi }}{3}} \right) $
$ \Rightarrow y = - \left( { - \sqrt 3 } \right) = \sqrt 3 $
Now we draw a table for these values we have
We also know the nature of the graph of sine function. Hence, we can now plot the graph of the given function $ y = - \tan \left( {2x} \right) $ . The nature of the graph of a function and its slope can also be determined from the derivative of the function. The graph plotted for these points is represented below:
Note: The graph is plotted x-axis versus y axis. The graph is two dimensional. By the equation of a graph, we can plot the graph by assuming the value of x. We can’t assume the value of y because the value of y depends on the value of x. The period of tangent function is $ \pi $ .
Complete step-by-step answer:
Here, in the given question, we have to plot the graph for the given function. A graph of a function is a set of ordered pairs and it is represented as $ y = f\left( x \right) $ , where x and $ f\left( x \right) $ are real numbers. These pairs are in the form of cartesian form and the graph is the two-dimensional graph.
First, we have to find the value of y by using the graph equation $ y = - \tan \left( {2x} \right) $ .
Let us substitute the value of x as $ \dfrac{\pi }{2} $ .
$ \Rightarrow y = - \tan \left( {2 \times \dfrac{\pi }{2}} \right) = - \tan \left( \pi \right) $
$ \Rightarrow y = 0 $
Let us substitute the value of x as $ 0 $ .
$ \Rightarrow y = - \tan \left( {2 \times 0} \right) = - \tan \left( 0 \right) $
$ \Rightarrow y = 0 $
Now we consider the value of x as $ \dfrac{\pi }{6} $ , the value of y is
$ \Rightarrow y = - \tan \left( {2 \times \dfrac{\pi }{6}} \right) = - \tan \left( {\dfrac{\pi }{3}} \right) $
$ \Rightarrow y = - \sqrt 3 $
Now we consider the value of x as $ \left( {\dfrac{\pi }{3}} \right) $ , the value of y is
$ \Rightarrow y = - \tan \left( {2 \times \dfrac{\pi }{3}} \right) = - \tan \left( {\dfrac{{2\pi }}{3}} \right) $
$ \Rightarrow y = - \left( { - \sqrt 3 } \right) = \sqrt 3 $
Now we draw a table for these values we have
| x | $ \dfrac{\pi }{2} $ | $ \dfrac{\pi }{3} $ | $ \left( {\dfrac{\pi }{6}} \right) $ | $ 0 $ |
| y | $ 0 $ | $ \sqrt 3 $ | $ - \sqrt 3 $ | 0 |
We also know the nature of the graph of sine function. Hence, we can now plot the graph of the given function $ y = - \tan \left( {2x} \right) $ . The nature of the graph of a function and its slope can also be determined from the derivative of the function. The graph plotted for these points is represented below:
Note: The graph is plotted x-axis versus y axis. The graph is two dimensional. By the equation of a graph, we can plot the graph by assuming the value of x. We can’t assume the value of y because the value of y depends on the value of x. The period of tangent function is $ \pi $ .
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

Which animal has three hearts class 11 biology CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

