
How do you graph \[y = - 3x + 3\] using a table?
Answer
518.1k+ views
Hint: We need to draw the graph ‘x’ versus ‘y’. Normally we give the random values for ‘x’ and we find the value of ‘y’. If we give all the real number values of ‘x’ we will get a decimal point of ‘y’ which is difficult to point out the coordinate in the graph. So we give all the real values for ‘y’ and we find the ‘x’ values. Thus we will have coordinate points (x, y). Hence, we can plot the graph by using the values. We can also draw the graph using the intercept method. But here we have a function which is passing through origin. So we use tables to draw the graph.
Complete step-by-step solution:
Given \[y = - 3x + 3\].
Let's give the values for ‘x’ and we find the value of ‘y’.
Put \[x = 1\]in \[y = - 3x + 3\] we have,
\[
\Rightarrow y = - 3x + 3 \\
\Rightarrow y = - 3\left( 1 \right) + 3 \\
\Rightarrow y = - 3 + 3 \\
\Rightarrow y = 0 \\
\]
Thus we have coordinate point \[(1,0)\].
Put \[x = - 1\]in \[y = - 3x + 3\] we have,
\[
\Rightarrow y = - 3x + 3 \\
\Rightarrow y = - 3\left( { - 1} \right) + 3 \\
\Rightarrow y = 3 + 3 \\
\Rightarrow y = 6 \\
\]
Thus we have coordinate points \[( - 1,6)\].
Put \[x = 2\]in \[y = - 3x + 3\] we have,
\[
\Rightarrow y = - 3x + 3 \\
\Rightarrow y = - 3\left( 2 \right) + 3 \\
\Rightarrow y = - 6 + 3 \\
\Rightarrow y = - 3 \\
\]
Thus we have coordinate points \[(2, - 3)\].
Put \[x = - 2\]in \[y = - 3x + 3\] we have,
\[
\Rightarrow y = - 3x + 3 \\
\Rightarrow y = - 3\left( { - 2} \right) + 3 \\
\Rightarrow y = 6 + 3 \\
\Rightarrow y = 9 \\
\]
Thus we have coordinate point \[( - 2,9)\].
Let’s draw the graph for these coordinates,
Here we take x-axis = 1 unit
y-axis = 1 unit =1 unit.
Note: We can see that the given curve is parabola. A graph shows the relation between two variable quantities, it contains two axes perpendicular to each other namely the x-axis and the y-axis. Each variable is measured along one of the axes. In the question, we are given one linear equation containing two variables namely x and y, x is measured along the x-axis and y is measured along the y-axis while tracing the given equations.
Complete step-by-step solution:
Given \[y = - 3x + 3\].
Let's give the values for ‘x’ and we find the value of ‘y’.
Put \[x = 1\]in \[y = - 3x + 3\] we have,
\[
\Rightarrow y = - 3x + 3 \\
\Rightarrow y = - 3\left( 1 \right) + 3 \\
\Rightarrow y = - 3 + 3 \\
\Rightarrow y = 0 \\
\]
Thus we have coordinate point \[(1,0)\].
Put \[x = - 1\]in \[y = - 3x + 3\] we have,
\[
\Rightarrow y = - 3x + 3 \\
\Rightarrow y = - 3\left( { - 1} \right) + 3 \\
\Rightarrow y = 3 + 3 \\
\Rightarrow y = 6 \\
\]
Thus we have coordinate points \[( - 1,6)\].
Put \[x = 2\]in \[y = - 3x + 3\] we have,
\[
\Rightarrow y = - 3x + 3 \\
\Rightarrow y = - 3\left( 2 \right) + 3 \\
\Rightarrow y = - 6 + 3 \\
\Rightarrow y = - 3 \\
\]
Thus we have coordinate points \[(2, - 3)\].
Put \[x = - 2\]in \[y = - 3x + 3\] we have,
\[
\Rightarrow y = - 3x + 3 \\
\Rightarrow y = - 3\left( { - 2} \right) + 3 \\
\Rightarrow y = 6 + 3 \\
\Rightarrow y = 9 \\
\]
Thus we have coordinate point \[( - 2,9)\].
| \[x\] | \[1\] | \[ - 1\] | \[2\] | \[ - 2\] |
| \[y\] | \[0\] | \[6\] | \[ - 3\] | \[9\] |
Let’s draw the graph for these coordinates,
Here we take x-axis = 1 unit
y-axis = 1 unit =1 unit.
Note: We can see that the given curve is parabola. A graph shows the relation between two variable quantities, it contains two axes perpendicular to each other namely the x-axis and the y-axis. Each variable is measured along one of the axes. In the question, we are given one linear equation containing two variables namely x and y, x is measured along the x-axis and y is measured along the y-axis while tracing the given equations.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 8 Maths: Engaging Questions & Answers for Success

Class 8 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Which of the following does not have a fundamental class 10 physics CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

