
How do you graph the linear system and estimate the solution: \[y=-x,y=2x+3\]?
Answer
547.8k+ views
Hint: A straight line in the form \[y=mx+c\] has slope m and y-intercept c. We can graph any straight line using any two points lying on it. Two intersecting straight lines meet at a common point which lies on both the lines. A point coordinate can be found based on its distance from each axis.
Complete step by step answer:
As per the given question, we have to graph the given two straight lines and find their intersecting point if they are intersecting lines. The given two straight lines are \[y=-x,y=2x+3\].
We can graph any line based on their intersecting points at x and y axes. For the first line equation \[y=-x\], a point lies on the x-axis when y is zero and it lies on y-axis if x is zero. Since there’s no constant term and slope is -1, the line passes through the origin bisecting the second and fourth quadrants.
For the second line \[y=2x+3\], when \[x=0\], \[y=2x+3=2(0)+3=3\] and when \[y=0\],
\[\Rightarrow y=2x+3\to 0=2x+3\to x=\dfrac{-3}{2}\]. So, \[(0,3)\] and \[(\dfrac{-3}{2},0)\] are the points on the line at y-axis and x-axis respectively.
Here, one line has a negative slope and the other has a positive slope. So, both intersect at a point.
The following graph shows the two straight lines intersecting each other at a point:
The graph shows the intersection point of the two lines as \[(-1,1)\].
Verification: -
We have the lines \[y=-x\] and \[y=2x+3\]. Substituting equation (1) in equation (2), we get
\[\begin{align}
& \Rightarrow y=2x+3 \\
& \Rightarrow -x=2x+3 \\
& \Rightarrow -x-2x=3 \\
& \Rightarrow -3x=3 \\
& \Rightarrow x=-1 \\
\end{align}\]
Substituting \[x=-1\] in the equation (1), we get
\[\begin{align}
& \Rightarrow y=-x \\
& \Rightarrow y=-(-1) \\
& \Rightarrow y=1 \\
\end{align}\]
Hence, verified.
\[\therefore (-1,1)\] is the solution of the lines \[y=-x,y=2x+3\].
Note: In order to solve these types of problems, we need to have knowledge over straight lines and their intersection condition. We should know about how to graph a straight line and to read the intersection point of two intersecting straight lines based on the graph. We should avoid calculation mistakes to get the correct solution.
Complete step by step answer:
As per the given question, we have to graph the given two straight lines and find their intersecting point if they are intersecting lines. The given two straight lines are \[y=-x,y=2x+3\].
We can graph any line based on their intersecting points at x and y axes. For the first line equation \[y=-x\], a point lies on the x-axis when y is zero and it lies on y-axis if x is zero. Since there’s no constant term and slope is -1, the line passes through the origin bisecting the second and fourth quadrants.
For the second line \[y=2x+3\], when \[x=0\], \[y=2x+3=2(0)+3=3\] and when \[y=0\],
\[\Rightarrow y=2x+3\to 0=2x+3\to x=\dfrac{-3}{2}\]. So, \[(0,3)\] and \[(\dfrac{-3}{2},0)\] are the points on the line at y-axis and x-axis respectively.
Here, one line has a negative slope and the other has a positive slope. So, both intersect at a point.
The following graph shows the two straight lines intersecting each other at a point:
The graph shows the intersection point of the two lines as \[(-1,1)\].
Verification: -
We have the lines \[y=-x\] and \[y=2x+3\]. Substituting equation (1) in equation (2), we get
\[\begin{align}
& \Rightarrow y=2x+3 \\
& \Rightarrow -x=2x+3 \\
& \Rightarrow -x-2x=3 \\
& \Rightarrow -3x=3 \\
& \Rightarrow x=-1 \\
\end{align}\]
Substituting \[x=-1\] in the equation (1), we get
\[\begin{align}
& \Rightarrow y=-x \\
& \Rightarrow y=-(-1) \\
& \Rightarrow y=1 \\
\end{align}\]
Hence, verified.
\[\therefore (-1,1)\] is the solution of the lines \[y=-x,y=2x+3\].
Note: In order to solve these types of problems, we need to have knowledge over straight lines and their intersection condition. We should know about how to graph a straight line and to read the intersection point of two intersecting straight lines based on the graph. We should avoid calculation mistakes to get the correct solution.
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