
How do you graph the line given \[\left( -2,3 \right)\], $m=0$ ?
Answer
550.8k+ views
Hint: Problems of graph plotting can be easily solved by using the general equation of a straight line which is: $y=mx+c$ . We must first put the given coordinates and the value of $m$ (slope) in the general equation to get the actual equation of the straight line. After getting the equation of the straight line which is a line parallel to $y-axis$ we can plot it on the graph paper.
Complete step by step answer:
Any straight line can be easily plotted on the graph paper by taking a general equation of a straight line: $y=mx+c$
The coordinates of point $\left( -2,3 \right)$ is already given and we know that this point lies on the straight line. So, we will put $-2$ in place of $x$ and $3$ in place of $y$ .
Hence, we get the relation between $c$ and $m$ , which is $3=-2m+c$
Now, we further put $m=0$, in the above relation and we get $c=3$ .
After putting the value of $m$ and $c$ in the general equation of the line we get the actual equation of the straight line which is $y=3$ .
As the slope $m$of the straight line is $0$ here, we can state that this line is parallel to $x$ -axis, that means the graph of this line is a horizontal line running through the $y$ -intercept at $\left( 0,3 \right)$ and must include the point \[\left( -2,3 \right)\].
Note: While solving graph problems of this type we must be careful while putting the coordinates in place of $x$, $y$ and $m$ to get the exact value of $c$ . Also, we must take additional care about putting the coordinates on the graph paper, as slight mistakes while plotting can degrade the quality of the graphed line.
Complete step by step answer:
Any straight line can be easily plotted on the graph paper by taking a general equation of a straight line: $y=mx+c$
The coordinates of point $\left( -2,3 \right)$ is already given and we know that this point lies on the straight line. So, we will put $-2$ in place of $x$ and $3$ in place of $y$ .
Hence, we get the relation between $c$ and $m$ , which is $3=-2m+c$
Now, we further put $m=0$, in the above relation and we get $c=3$ .
After putting the value of $m$ and $c$ in the general equation of the line we get the actual equation of the straight line which is $y=3$ .
As the slope $m$of the straight line is $0$ here, we can state that this line is parallel to $x$ -axis, that means the graph of this line is a horizontal line running through the $y$ -intercept at $\left( 0,3 \right)$ and must include the point \[\left( -2,3 \right)\].
Note: While solving graph problems of this type we must be careful while putting the coordinates in place of $x$, $y$ and $m$ to get the exact value of $c$ . Also, we must take additional care about putting the coordinates on the graph paper, as slight mistakes while plotting can degrade the quality of the graphed line.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Who among the following opened first school for girls class 9 social science CBSE

What does the word meridian mean A New day B Midday class 9 social science CBSE

What is the full form of pH?

Write the 6 fundamental rights of India and explain in detail

Which places in India experience sunrise first and class 9 social science CBSE

