
How do you graph the function $y = 5x + 1?$
Answer
542.4k+ views
Hint:Find two (minimum) or more points that satisfy the given equation i.e. $y = 5x + 1$ Plot them on a graph paper and then join them with the help of a straight line.
Complete Step-by-step answer-
As the given equation is the linear form of equation in two-variables, you will get a straight line.
Given-
$y = 5x + 1$
At $x = 0$ ; $y = 5(0) + 1$ $ = 1$
Therefore, we got our first point that will satisfy the equation which is (0,1) . It is Y intercept.
At $y = 0$ ;$5x + 1 = 0$
$ \Rightarrow x = \dfrac{{ - 1}}{5}$
Hence, we got another point that will satisfy the equation and is equal to ($\left( { - \dfrac{1}{5},0} \right)$
Since it is a fraction, we will try to find another point which has two integers as coordinates.
At $y = 6$ ; $5x + 1 = 6$
$ \Rightarrow x = \dfrac{5}{5} = 1$
Therefore, the second required point is (1,6).
Plot points (0,1) and (1,6) on the graph sheet. Join these two points and you will get the required graph .
Note- The coordinates can vary according to the choice you make but all the points should satisfy the given equation of the straight line.
Complete Step-by-step answer-
As the given equation is the linear form of equation in two-variables, you will get a straight line.
Given-
$y = 5x + 1$
At $x = 0$ ; $y = 5(0) + 1$ $ = 1$
Therefore, we got our first point that will satisfy the equation which is (0,1) . It is Y intercept.
At $y = 0$ ;$5x + 1 = 0$
$ \Rightarrow x = \dfrac{{ - 1}}{5}$
Hence, we got another point that will satisfy the equation and is equal to ($\left( { - \dfrac{1}{5},0} \right)$
Since it is a fraction, we will try to find another point which has two integers as coordinates.
At $y = 6$ ; $5x + 1 = 6$
$ \Rightarrow x = \dfrac{5}{5} = 1$
Therefore, the second required point is (1,6).
Plot points (0,1) and (1,6) on the graph sheet. Join these two points and you will get the required graph .
Note- The coordinates can vary according to the choice you make but all the points should satisfy the given equation of the straight line.
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