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How many grams of sodium is present in 2 moles?

Answer
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540.9k+ views
Hint: This is a very easy question which can be solved easily if we know the atomic mass of sodium. After we get to know the atomic mass of sodium, we can multiply it with the number of moles asked to us in the question. The final result obtained after multiplying it with the number of moles is our required answer to this particular question.

Formula Used
 $ {\text{moles}} = \dfrac{{{\text{mass}}}}{{{\text{molar mass}}}} $

Complete Step By Step Answer
We know that the atomic mass of sodium is $ 23{\text{ g mo}}{{\text{l}}^{{\text{ - 1}}}} $
That is
 $ 23 $ gram sodium has $ 1 $ mole in it
So, we need to calculate the number of grams in $ 2 $ moles of sodium
We can do so by using a simple unitary method.
 $ 1 $ mole of sodium is present in $ 23 $ grams
Then the number of grams in $ 2 $ grams of sodium is given by
 $ \dfrac{{23 {\text{g mo}}{{\text{l}}^{{\text{ - 1}}}}}}{{1 {\text{mol}}}} \times 2 {\text{g}} = 46 {\text{g}} $
Hence, the number of grams of sodium is present in $ 2 $ moles is $ 46 {\text{g}} $ .

Additional Information:
The number $ 6.022 \times {10^{23}} $ is commonly referred to as the constant of Avogadro and is often denoted by the ' $ {N_A} $ ' symbol. It is the number of particles present in one mole of any substance. Atoms, molecules, monatomic/polyatomic ions, and other particles can be the fundamental entities (such as electrons) that can be represented in moles.

Note:
Even one gram of a pure element is known to contain an enormous number of atoms when dealing with particles at an atomic (or molecular) level. This is where it is widely used to use the mole concept. It focuses primarily on the unit known as a mole, which is a very large number of particles counted.