Question

How many grams of ${O_2}$will produce from $12moles$ of $NaCl{O_3}$ ?$2NaCl{O_3} \to 2NaCl + 3{O_2}$

Answer 1

Hint:To solve this question, we can use the concept of stoichiometry. Stoichiometry can be defined as a branch of chemistry that involves using the relationships between reactants or products in a chemical reaction to obtain the desired quantitative data. Stoichiometric coefficient is the number which is written in front of the atoms, ions, or molecules in a chemical reaction in order to balance the number of each element on both sides of the equation.

Complete step-by-step answer:
As we know the reaction is given by,
$2NaCl{O_3} \to 2NaCl + 3{O_2}$
From this we can deduce the mole ratio between $NaCl{O_3}:{O_2}$ which is $2:3$
Molar mass of oxygen which is $32g/mol$
Since we have to find grams of oxygen from $12moles$of $NaCl{O_3}$ , we first need to find moles of oxygen then convert to grams of oxygen.
Hence, equation to find out grams of oxygen produced from $12moles$ of $NaCl{O_3}$ is given by,
$12molNaCl{O_3} \times \dfrac{{3mol{O_2}}}{{2molNaCl{O_3}}} \times \dfrac{{32g{O_2}}}{{1mol{O_2}}} = 576g{O_2}$
Hence, $576g{O_2}$ is produced from $12moles$ of $NaCl{O_3}$

Additional information:The most common type of stoichiometric relationship is the mole ratio, which relates the amounts in moles of any two substances in a chemical reaction. We can write a mole ratio for a pair of substances by looking at the coefficients in front of each species in the balanced chemical equation. 

Note:Stoichiometry is based on the law of conservation of mass where the total mass of the reactants is equal to the total mass of the products, which means that the relations among quantities of reactants and products form a ratio of positive integers. Hence, we can say that, if the amounts of the separate reactants are known, then the amount of the product can be calculated.