Question

How many grams of $CaO$ is required to neutralize the 852 g of \[{P_4}{O_{10}}\]?

Answer 1

Hint:To determine the amount of $CaO$ required firstly, we have to write the balanced chemical reaction for the above condition. Then, from that reaction we can find how many moles of $CaO$ is required to neutralize the \[{P_4}{O_{10}}\]. Here, we have to use the mole concept to answer this question.

Complete step-by-step solution:Let us write the balanced chemical equation for the above condition.
$6\;CaO\; + \;{P_4}{O_{10}}\; \to \;2\;C{a_3}{\left( {P{O_4}} \right)_2}$
Now, from the above reaction we can say that 6 moles of $CaO$ will neutralize the 1 mole of \[{P_4}{O_{10}}\]. From this we can now find the grams of $CaO$ required to neutralize the 852 g of \[{P_4}{O_{10}}\] .
According to the mole concept; One mole of any substance is equal to the molar mass of that substance. So now we know the molar masses of the $CaO$and \[{P_4}{O_{10}}\]. Then from that relation we can find the grams of $CaO$.
Here, Molar mass of $CaO$ = 56.07 $g\;mo{l^ - }$ and Molar mass of \[{P_4}{O_{10}}\] = 283.88 $g\;mo{l^ - }$.
Therefore, we can find; 1 mole of $CaO$ = 56.07 $g\;mo{l^ - }$
6 moles of $CaO$ =?
$Grams\;of\;CaO\;in\;6\;moles\; = \dfrac{{6\;mole \times 56.07\;g\;mo{l^ - }}}{{1\;mole}}$
Grams of Cao in 6 moles = 336.42 $g\;mo{l^ - }$
So, from above it is clear that 336.42 grams of Cao Neutralize the 283.88 grams of \[{P_4}{O_{10}}\].
Hence, we can find the grams of $CaO$ required for 852 g of \[{P_4}{O_{10}}\]
i.e. Here, 336.42 g $CaO$ = 283.88 g \[{P_4}{O_{10}}\]
How many g $CaO$ ? = 852 g \[{P_4}{O_{10}}\]
$Grams\;of\;Cao\;required\; = \;\dfrac{{336.42\;g \times 852\;g}}{{283.88\;g}}$
Grams of Cao required = 1009 g.

Note:So, here we can say that the 1009 g of Cao is required to neutralize the 852 g of \[{P_4}{O_{10}}\].This is calculated by using the mole concept and by taking the balanced chemical reaction. It is necessary to take balanced chemical reactions to solve these types of questions. Mole concept is saying that one mole of any substance is equal to the molar mass of that substance.