How many gram of ${\text{C}}{{\text{O}}_{\text{2}}}$ would be needed to have the same number of moles of ${\text{C}}{{\text{O}}_{\text{2}}}$ as there are in ${\text{52}}{\text{.2}}$ grams of ${{\text{H}}_2}{\text{O}}$?
Answer
598.2k+ views
Hint: The mass of water is also given so we can calculate the moles of water by using mole formula. It is given that moles of carbon dioxide and water are the same. So, we can use the moles of water as the moles of carbon dioxide. By using mole formula we can determine the mass of carbon dioxide.
Complete step by step solution:
We will use the mole formula to determine the number of moles of water as follows:
${\text{mole}}\,{\text{ = }}\,\dfrac{{{\text{mass}}}}{{{\text{molar}}\,{\text{mass}}}}$
Molar mass of water is $18.01$ g/mol.
On substituting $52.2$ grams for mass of water and $18.01$for molar mass of water,
${\text{mole}}\,{\text{ = }}\,\dfrac{{52.2}}{{18.01}}$
${\text{mole}}\,{\text{ = }}2.89$
So, the moles of the water is $2.89$.
It is given that ${\text{C}}{{\text{O}}_{\text{2}}}$have the same number of moles of as there are in ${\text{52}}{\text{.2}}$ grams of ${{\text{H}}_2}{\text{O}}$. So, the number of moles of ${\text{C}}{{\text{O}}_{\text{2}}}$ is also $2.89$ mol.
We will use the mole formula to determine the mass of ${\text{C}}{{\text{O}}_{\text{2}}}$ as follows:
${\text{mole}}\,{\text{ = }}\,\dfrac{{{\text{mass}}}}{{{\text{molar}}\,{\text{mass}}}}$
Molar mass of ${\text{C}}{{\text{O}}_{\text{2}}}$is $44.00$ g/mol.
On substituting $2.89$ mol for moles of ${\text{C}}{{\text{O}}_{\text{2}}}$and $44.00$for molar mass of${\text{C}}{{\text{O}}_{\text{2}}}$,
${\text{2}}{\text{.89}}\,{\text{mol}}\,{\text{ = }}\,\dfrac{{{\text{mass}}}}{{{\text{44}}{\text{.00}}\,{\text{g/mol}}}}$
${\text{mass}}\, = \,{\text{2}}{\text{.89}}\,{\text{mol}}\,\, \times \,{\text{44}}{\text{.00}}\,{\text{g/mol}}$
${\text{mass}}\, = \,127.53\,{\text{g}}$
So, the mass of ${\text{C}}{{\text{O}}_{\text{2}}}$is $127.53$ grams.
So, $127.53$ grams of ${\text{C}}{{\text{O}}_{\text{2}}}$ would be needed to have the same number of moles of ${\text{C}}{{\text{O}}_{\text{2}}}$ as there are in ${\text{52}}{\text{.2}}$ grams of ${{\text{H}}_2}{\text{O}}$.
Therefore, $127.53$ grams is the correct answer.
Note: The number of atoms present in $12\,{\text{g}}$ of carbon-12 is known as one mole. The molar mass of water is the sum of atomic mass of two hydrogen atoms and one oxygen atom. The molar mass of carbon dioxide is the sum of atomic mass of one carbon atom and two oxygen atoms. The unit of molar mass is gram per mole. The unit of mass is gram.
Complete step by step solution:
We will use the mole formula to determine the number of moles of water as follows:
${\text{mole}}\,{\text{ = }}\,\dfrac{{{\text{mass}}}}{{{\text{molar}}\,{\text{mass}}}}$
Molar mass of water is $18.01$ g/mol.
On substituting $52.2$ grams for mass of water and $18.01$for molar mass of water,
${\text{mole}}\,{\text{ = }}\,\dfrac{{52.2}}{{18.01}}$
${\text{mole}}\,{\text{ = }}2.89$
So, the moles of the water is $2.89$.
It is given that ${\text{C}}{{\text{O}}_{\text{2}}}$have the same number of moles of as there are in ${\text{52}}{\text{.2}}$ grams of ${{\text{H}}_2}{\text{O}}$. So, the number of moles of ${\text{C}}{{\text{O}}_{\text{2}}}$ is also $2.89$ mol.
We will use the mole formula to determine the mass of ${\text{C}}{{\text{O}}_{\text{2}}}$ as follows:
${\text{mole}}\,{\text{ = }}\,\dfrac{{{\text{mass}}}}{{{\text{molar}}\,{\text{mass}}}}$
Molar mass of ${\text{C}}{{\text{O}}_{\text{2}}}$is $44.00$ g/mol.
On substituting $2.89$ mol for moles of ${\text{C}}{{\text{O}}_{\text{2}}}$and $44.00$for molar mass of${\text{C}}{{\text{O}}_{\text{2}}}$,
${\text{2}}{\text{.89}}\,{\text{mol}}\,{\text{ = }}\,\dfrac{{{\text{mass}}}}{{{\text{44}}{\text{.00}}\,{\text{g/mol}}}}$
${\text{mass}}\, = \,{\text{2}}{\text{.89}}\,{\text{mol}}\,\, \times \,{\text{44}}{\text{.00}}\,{\text{g/mol}}$
${\text{mass}}\, = \,127.53\,{\text{g}}$
So, the mass of ${\text{C}}{{\text{O}}_{\text{2}}}$is $127.53$ grams.
So, $127.53$ grams of ${\text{C}}{{\text{O}}_{\text{2}}}$ would be needed to have the same number of moles of ${\text{C}}{{\text{O}}_{\text{2}}}$ as there are in ${\text{52}}{\text{.2}}$ grams of ${{\text{H}}_2}{\text{O}}$.
Therefore, $127.53$ grams is the correct answer.
Note: The number of atoms present in $12\,{\text{g}}$ of carbon-12 is known as one mole. The molar mass of water is the sum of atomic mass of two hydrogen atoms and one oxygen atom. The molar mass of carbon dioxide is the sum of atomic mass of one carbon atom and two oxygen atoms. The unit of molar mass is gram per mole. The unit of mass is gram.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Difference between physical and chemical change class 11 chemistry CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

