How many gram of ${\text{C}}{{\text{O}}_{\text{2}}}$ would be needed to have the same number of moles of ${\text{C}}{{\text{O}}_{\text{2}}}$ as there are in ${\text{52}}{\text{.2}}$ grams of ${{\text{H}}_2}{\text{O}}$?
Answer
575.7k+ views
Hint: The mass of water is also given so we can calculate the moles of water by using mole formula. It is given that moles of carbon dioxide and water are the same. So, we can use the moles of water as the moles of carbon dioxide. By using mole formula we can determine the mass of carbon dioxide.
Complete step by step solution:
We will use the mole formula to determine the number of moles of water as follows:
${\text{mole}}\,{\text{ = }}\,\dfrac{{{\text{mass}}}}{{{\text{molar}}\,{\text{mass}}}}$
Molar mass of water is $18.01$ g/mol.
On substituting $52.2$ grams for mass of water and $18.01$for molar mass of water,
${\text{mole}}\,{\text{ = }}\,\dfrac{{52.2}}{{18.01}}$
${\text{mole}}\,{\text{ = }}2.89$
So, the moles of the water is $2.89$.
It is given that ${\text{C}}{{\text{O}}_{\text{2}}}$have the same number of moles of as there are in ${\text{52}}{\text{.2}}$ grams of ${{\text{H}}_2}{\text{O}}$. So, the number of moles of ${\text{C}}{{\text{O}}_{\text{2}}}$ is also $2.89$ mol.
We will use the mole formula to determine the mass of ${\text{C}}{{\text{O}}_{\text{2}}}$ as follows:
${\text{mole}}\,{\text{ = }}\,\dfrac{{{\text{mass}}}}{{{\text{molar}}\,{\text{mass}}}}$
Molar mass of ${\text{C}}{{\text{O}}_{\text{2}}}$is $44.00$ g/mol.
On substituting $2.89$ mol for moles of ${\text{C}}{{\text{O}}_{\text{2}}}$and $44.00$for molar mass of${\text{C}}{{\text{O}}_{\text{2}}}$,
${\text{2}}{\text{.89}}\,{\text{mol}}\,{\text{ = }}\,\dfrac{{{\text{mass}}}}{{{\text{44}}{\text{.00}}\,{\text{g/mol}}}}$
${\text{mass}}\, = \,{\text{2}}{\text{.89}}\,{\text{mol}}\,\, \times \,{\text{44}}{\text{.00}}\,{\text{g/mol}}$
${\text{mass}}\, = \,127.53\,{\text{g}}$
So, the mass of ${\text{C}}{{\text{O}}_{\text{2}}}$is $127.53$ grams.
So, $127.53$ grams of ${\text{C}}{{\text{O}}_{\text{2}}}$ would be needed to have the same number of moles of ${\text{C}}{{\text{O}}_{\text{2}}}$ as there are in ${\text{52}}{\text{.2}}$ grams of ${{\text{H}}_2}{\text{O}}$.
Therefore, $127.53$ grams is the correct answer.
Note: The number of atoms present in $12\,{\text{g}}$ of carbon-12 is known as one mole. The molar mass of water is the sum of atomic mass of two hydrogen atoms and one oxygen atom. The molar mass of carbon dioxide is the sum of atomic mass of one carbon atom and two oxygen atoms. The unit of molar mass is gram per mole. The unit of mass is gram.
Complete step by step solution:
We will use the mole formula to determine the number of moles of water as follows:
${\text{mole}}\,{\text{ = }}\,\dfrac{{{\text{mass}}}}{{{\text{molar}}\,{\text{mass}}}}$
Molar mass of water is $18.01$ g/mol.
On substituting $52.2$ grams for mass of water and $18.01$for molar mass of water,
${\text{mole}}\,{\text{ = }}\,\dfrac{{52.2}}{{18.01}}$
${\text{mole}}\,{\text{ = }}2.89$
So, the moles of the water is $2.89$.
It is given that ${\text{C}}{{\text{O}}_{\text{2}}}$have the same number of moles of as there are in ${\text{52}}{\text{.2}}$ grams of ${{\text{H}}_2}{\text{O}}$. So, the number of moles of ${\text{C}}{{\text{O}}_{\text{2}}}$ is also $2.89$ mol.
We will use the mole formula to determine the mass of ${\text{C}}{{\text{O}}_{\text{2}}}$ as follows:
${\text{mole}}\,{\text{ = }}\,\dfrac{{{\text{mass}}}}{{{\text{molar}}\,{\text{mass}}}}$
Molar mass of ${\text{C}}{{\text{O}}_{\text{2}}}$is $44.00$ g/mol.
On substituting $2.89$ mol for moles of ${\text{C}}{{\text{O}}_{\text{2}}}$and $44.00$for molar mass of${\text{C}}{{\text{O}}_{\text{2}}}$,
${\text{2}}{\text{.89}}\,{\text{mol}}\,{\text{ = }}\,\dfrac{{{\text{mass}}}}{{{\text{44}}{\text{.00}}\,{\text{g/mol}}}}$
${\text{mass}}\, = \,{\text{2}}{\text{.89}}\,{\text{mol}}\,\, \times \,{\text{44}}{\text{.00}}\,{\text{g/mol}}$
${\text{mass}}\, = \,127.53\,{\text{g}}$
So, the mass of ${\text{C}}{{\text{O}}_{\text{2}}}$is $127.53$ grams.
So, $127.53$ grams of ${\text{C}}{{\text{O}}_{\text{2}}}$ would be needed to have the same number of moles of ${\text{C}}{{\text{O}}_{\text{2}}}$ as there are in ${\text{52}}{\text{.2}}$ grams of ${{\text{H}}_2}{\text{O}}$.
Therefore, $127.53$ grams is the correct answer.
Note: The number of atoms present in $12\,{\text{g}}$ of carbon-12 is known as one mole. The molar mass of water is the sum of atomic mass of two hydrogen atoms and one oxygen atom. The molar mass of carbon dioxide is the sum of atomic mass of one carbon atom and two oxygen atoms. The unit of molar mass is gram per mole. The unit of mass is gram.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Which among the following are examples of coming together class 11 social science CBSE

Discuss the various forms of bacteria class 11 biology CBSE

What organs are located on the left side of your body class 11 biology CBSE

Draw a labelled diagram showing structure of LS of class 11 biology CBSE

