
How many gm of bromine will react with 21 gm C3H6
A. 80
B. 160
C. 240
D. 320
Answer
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Hint: In this question we have to use the reaction between bromine and propene to find out the amount of bromine that will react with 21 gm of propene. Unsaturated molecule C3H6 (propene) reacts with bromine to produce a decoloured product.
Complete Step by Step Answer:
Alkenes with pure liquid bromine or a bromine solution in an organic solvent, such as tetrachloromethane, react in the cold. Each carbon now has a bromine atom connected to it when the double bond dissolves. The bromine turns into a colourless liquid after losing its original reddish-brown hue. 1,2-dibromoethane is created when the reaction with ethene occurs.
When bromine and propene interact, the double bond dissolves and a bromine atom is joined to each carbon. The product of this reaction with propene is 1,2-dibromopropane. The reaction is an example of electrophilic addition. The bromine is a very "polarizable" molecule and the approaching pi bond in the proene induces a dipole in the bromine molecule.
Chemical reaction involved:
CH3-CH=CH2 + Br2 → CH3-CH2Br-CH2
One mole of propene reacts with 1 mole of Br2 to give 1 mole of 1,1 dibromopropane. From the mole concept, 21 grams of propene means moles of propene. Therefore, we need 0.5 moles of Br2 gas. That is, we need 80 gms of bromine.
The correct answer is A.
Note: Apart from fluorine, the other halogens exhibit comparable behaviour. Each carbon now has a halogen atom connected to it when the double bond dissolves. All hydrocarbons, including alkenes, react violently with fluorine to produce carbon and hydrogen fluoride.
Complete Step by Step Answer:
Alkenes with pure liquid bromine or a bromine solution in an organic solvent, such as tetrachloromethane, react in the cold. Each carbon now has a bromine atom connected to it when the double bond dissolves. The bromine turns into a colourless liquid after losing its original reddish-brown hue. 1,2-dibromoethane is created when the reaction with ethene occurs.
When bromine and propene interact, the double bond dissolves and a bromine atom is joined to each carbon. The product of this reaction with propene is 1,2-dibromopropane. The reaction is an example of electrophilic addition. The bromine is a very "polarizable" molecule and the approaching pi bond in the proene induces a dipole in the bromine molecule.
Chemical reaction involved:
CH3-CH=CH2 + Br2 → CH3-CH2Br-CH2
One mole of propene reacts with 1 mole of Br2 to give 1 mole of 1,1 dibromopropane. From the mole concept, 21 grams of propene means moles of propene. Therefore, we need 0.5 moles of Br2 gas. That is, we need 80 gms of bromine.
The correct answer is A.
Note: Apart from fluorine, the other halogens exhibit comparable behaviour. Each carbon now has a halogen atom connected to it when the double bond dissolves. All hydrocarbons, including alkenes, react violently with fluorine to produce carbon and hydrogen fluoride.
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