
Glucose has a gram molecular mass of:
(A)\[180 \cdot 096u\]
(B) $180 \cdot 096g$
(C) $180 \cdot 0096u$
D) $18 \cdot 0096g$
Answer
577.5k+ views
Hint: Gram molecular mass is defined as the sum of the masses of all the atoms present in one molecule of a compound. Glucose is a simple six carbon sugar. It is the most abundant monosaccharide found in the living world and is the main product of photosynthesis.
Complete step by step answer:
Step 1: Consider the molecular formula of glucose, to find the elements involved in the formation of one molecule of Glucose.
The molecular formula of glucose $ = {{\text{C}}_6}{H_{12}}{O_6}$
Step 2: Find the atomic mass of each element present in the molecule.
Atomic mass of Carbon (C) $ = 12 \cdot 01g$
Atomic mass of Hydrogen (H) $ = 1 \cdot 008g$
Atomic mass of Oxygen (0)$ = 16 \cdot 00g$
Step 3: Calculate the total mass of each element present in the molecule.
From the molecular formula of glucose, we find that there are six atoms of carbon, twelve atoms of hydrogen and six atoms of oxygen in one molecule of glucose. Considering this data, we can find:
Total mass of carbon (C) in a molecule glucose will be,$\left( {12 \cdot 08 \times 6} \right)g = 72 \cdot 06g$
Total mass of Hydrogen(H) in a molecule glucose will be,$\left( {1.008 \times 12} \right)g = 12 \cdot 096g$
Total mass of Oxygen (O) in a molecule of glucose will be, $\left( {16 \cdot 00 \times 6} \right)g = 96.00g$
Step 4: Obtain the molecular mass of glucose by adding up the total mass of the individual element.
Therefore, the gram molecular mass of Glucose will be:
$\left( {72 \cdot 06 + 12 \cdot 096 + 96 \cdot 00} \right)g = 180 \cdot 096g$
From the above calculations we can conclude that, Option B is the correct choice.
Note:
Even though the numeric value of molecular mass and gram molecular mass is the same, there is a slight difference between the two. Whenever we refer molecular mass of a compound, we indicate the mass of one molecule of the compound relative to the mass of one C-12 atom and it is represented in atomic mass units (a.m.u.) but when we refer gram molecular mass, we indicate the mass of one mole of the compound in grams.
Complete step by step answer:
Step 1: Consider the molecular formula of glucose, to find the elements involved in the formation of one molecule of Glucose.
The molecular formula of glucose $ = {{\text{C}}_6}{H_{12}}{O_6}$
Step 2: Find the atomic mass of each element present in the molecule.
Atomic mass of Carbon (C) $ = 12 \cdot 01g$
Atomic mass of Hydrogen (H) $ = 1 \cdot 008g$
Atomic mass of Oxygen (0)$ = 16 \cdot 00g$
Step 3: Calculate the total mass of each element present in the molecule.
From the molecular formula of glucose, we find that there are six atoms of carbon, twelve atoms of hydrogen and six atoms of oxygen in one molecule of glucose. Considering this data, we can find:
Total mass of carbon (C) in a molecule glucose will be,$\left( {12 \cdot 08 \times 6} \right)g = 72 \cdot 06g$
Total mass of Hydrogen(H) in a molecule glucose will be,$\left( {1.008 \times 12} \right)g = 12 \cdot 096g$
Total mass of Oxygen (O) in a molecule of glucose will be, $\left( {16 \cdot 00 \times 6} \right)g = 96.00g$
Step 4: Obtain the molecular mass of glucose by adding up the total mass of the individual element.
Therefore, the gram molecular mass of Glucose will be:
$\left( {72 \cdot 06 + 12 \cdot 096 + 96 \cdot 00} \right)g = 180 \cdot 096g$
From the above calculations we can conclude that, Option B is the correct choice.
Note:
Even though the numeric value of molecular mass and gram molecular mass is the same, there is a slight difference between the two. Whenever we refer molecular mass of a compound, we indicate the mass of one molecule of the compound relative to the mass of one C-12 atom and it is represented in atomic mass units (a.m.u.) but when we refer gram molecular mass, we indicate the mass of one mole of the compound in grams.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

