
Given,\[NaHC{O_3}\] on heating gives-
Answer
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Hint: Chemical name of \[NaHC{O_3}\] is sodium bicarbonate. \[NaHC{O_3}\] is composed of sodium salt and carbonic acid. \[NaHC{O_3}\] contains only one atom of sodium therefore, it is also known as monosodium salt. \[NaHC{O_3}\] undergoes thermal decomposition to generate different products.
Complete answer:
\[NaHC{O_3}\] shows temperature dependent stability. \[NaHC{O_3}\] has a tendency to undergo the process of thermal decomposition to break down into constituents which are chemically more stable than sodium bicarbonate.
\[NaHC{O_3}\] is prepared by reaction of carbon dioxide gas, ammonia, and water in the presence of salt or sodium metal.
$C{O_2} + {H_2}O + N{H_2} + NaCl \to NaHCO + N{H_4}Cl$
Process of thermal decomposition is also done in the presence of light source, radiation or even electricity but in this chemical reaction the source of the process is heat.
When we gradually raise the temperature beyond $80$$^ \circ C$, sodium bicarbonate start dissociating and generate three major products-:
\[NaHC{O_3}\underrightarrow \Delta N{a_2}C{O_3} + {H_2}O + C{O_2}\]
Then we show Balanced chemical equation for thermal decomposition of sodium bicarbonate as: -
\[2NaHC{O_3}_{\left( s \right)}\underrightarrow \Delta N{a_2}C{O_3}_{\left( s \right)} + {H_2}{O_{\left( g \right)}} + C{O_2}_{\left( g \right)}\]
Hence from the above chemical reaction we observed that two moles of sodium bicarbonate undergo thermal decomposition over $80$$^ \circ C$ to form one molecule of sodium carbonate, one mole of water, and one of carbon dioxide gas.
The process of conversion of sodium bicarbonate into sodium carbonate is an example of endothermic reaction because this chemical reaction requires a heat source to initiate the process of decomposition.
This reaction is widely used in baking industries to impart puffiness in food items.
Note:
\[NaHC{O_3}\] is bitter in nature because it is alkaline in nature. It exists as odorless off-white powder. Sodium bicarbonate generates bicarbonate ions in the body which results in further increase of blood normal Ph. \[NaHC{O_3}\] is used as an approved fungicide to kill fungus which harm the plants.
Complete answer:
\[NaHC{O_3}\] shows temperature dependent stability. \[NaHC{O_3}\] has a tendency to undergo the process of thermal decomposition to break down into constituents which are chemically more stable than sodium bicarbonate.
\[NaHC{O_3}\] is prepared by reaction of carbon dioxide gas, ammonia, and water in the presence of salt or sodium metal.
$C{O_2} + {H_2}O + N{H_2} + NaCl \to NaHCO + N{H_4}Cl$
Process of thermal decomposition is also done in the presence of light source, radiation or even electricity but in this chemical reaction the source of the process is heat.
When we gradually raise the temperature beyond $80$$^ \circ C$, sodium bicarbonate start dissociating and generate three major products-:
\[NaHC{O_3}\underrightarrow \Delta N{a_2}C{O_3} + {H_2}O + C{O_2}\]
Then we show Balanced chemical equation for thermal decomposition of sodium bicarbonate as: -
\[2NaHC{O_3}_{\left( s \right)}\underrightarrow \Delta N{a_2}C{O_3}_{\left( s \right)} + {H_2}{O_{\left( g \right)}} + C{O_2}_{\left( g \right)}\]
Hence from the above chemical reaction we observed that two moles of sodium bicarbonate undergo thermal decomposition over $80$$^ \circ C$ to form one molecule of sodium carbonate, one mole of water, and one of carbon dioxide gas.
The process of conversion of sodium bicarbonate into sodium carbonate is an example of endothermic reaction because this chemical reaction requires a heat source to initiate the process of decomposition.
This reaction is widely used in baking industries to impart puffiness in food items.
Note:
\[NaHC{O_3}\] is bitter in nature because it is alkaline in nature. It exists as odorless off-white powder. Sodium bicarbonate generates bicarbonate ions in the body which results in further increase of blood normal Ph. \[NaHC{O_3}\] is used as an approved fungicide to kill fungus which harm the plants.
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