Given that one of the zeroes of the cubic polynomial \[a{x^3} + b{x^2} + cx + d\] is zero, the product of the other two zeroes is
A) \[ - \dfrac{c}{a}\]
B) \[\dfrac{c}{a}\]
C) 0
D) \[ - \dfrac{b}{a}\]
Answer
589.8k+ views
Hint:
Here we need to find the product of two zeroes of the given cubic polynomial. The zeroes of the polynomial means the roots of the polynomial. We will substitute the value of the given root in the cubic equation to get the value of constant of the cubic polynomial. Then we will put the value of constant in the equation. We will then get a quadratic equation. We will further solve the equation to find the zeros and multiply the obtained zeros to find the product.
Complete step by step solution:
We know zeroes of the polynomial means the roots of the polynomial.
It is given that 0 is the root of the given cubic polynomial, so it will satisfy the cubic equation.
Substituting the value of root in the cubic equation, \[a{x^3} + b{x^2} + cx + d\], we get
\[ \Rightarrow a{\left( 0 \right)^3} + b{\left( 0 \right)^2} + c\left( 0 \right) + d = 0\]
On further simplification, we get
\[ \Rightarrow d = 0\]
Thus, substituting the value of \[d\] , the cubic polynomial becomes
\[\begin{array}{l}a{x^3} + b{x^2} + cx + 0 = 0\\ \Rightarrow a{x^3} + b{x^2} + cx = 0\end{array}\]
We can write the equation as
\[ \Rightarrow x\left( {a{x^2} + bx + c} \right) = 0\]
Dividing the above equation by\[x\], we get
\[ \Rightarrow a{x^2} + bx + c = 0\]
The obtained equation is a quadratic equation and the product of roots of this equation is equal to the ratio of constant term i.e. \[c\] to the coefficient of \[{x^2}\].
Therefore, the product of roots of this quadratic equation is equal to \[\dfrac{c}{a}\].
Hence, the correct option is option B.
Note:
We need to keep in mind that the number of roots of the polynomial is always equal to the highest power in the polynomial. The number of roots of a quadratic polynomial is 2 because the highest power in a quadratic polynomial is 2. Similarly the number of roots of cubic polynomials is 3 because the highest power in cubic polynomials is 3.
Here we need to find the product of two zeroes of the given cubic polynomial. The zeroes of the polynomial means the roots of the polynomial. We will substitute the value of the given root in the cubic equation to get the value of constant of the cubic polynomial. Then we will put the value of constant in the equation. We will then get a quadratic equation. We will further solve the equation to find the zeros and multiply the obtained zeros to find the product.
Complete step by step solution:
We know zeroes of the polynomial means the roots of the polynomial.
It is given that 0 is the root of the given cubic polynomial, so it will satisfy the cubic equation.
Substituting the value of root in the cubic equation, \[a{x^3} + b{x^2} + cx + d\], we get
\[ \Rightarrow a{\left( 0 \right)^3} + b{\left( 0 \right)^2} + c\left( 0 \right) + d = 0\]
On further simplification, we get
\[ \Rightarrow d = 0\]
Thus, substituting the value of \[d\] , the cubic polynomial becomes
\[\begin{array}{l}a{x^3} + b{x^2} + cx + 0 = 0\\ \Rightarrow a{x^3} + b{x^2} + cx = 0\end{array}\]
We can write the equation as
\[ \Rightarrow x\left( {a{x^2} + bx + c} \right) = 0\]
Dividing the above equation by\[x\], we get
\[ \Rightarrow a{x^2} + bx + c = 0\]
The obtained equation is a quadratic equation and the product of roots of this equation is equal to the ratio of constant term i.e. \[c\] to the coefficient of \[{x^2}\].
Therefore, the product of roots of this quadratic equation is equal to \[\dfrac{c}{a}\].
Hence, the correct option is option B.
Note:
We need to keep in mind that the number of roots of the polynomial is always equal to the highest power in the polynomial. The number of roots of a quadratic polynomial is 2 because the highest power in a quadratic polynomial is 2. Similarly the number of roots of cubic polynomials is 3 because the highest power in cubic polynomials is 3.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

In cricket, what is the term for a bowler taking five wickets in an innings?

Who Won 36 Oscar Awards? Record Holder Revealed

What is the median of the first 10 natural numbers class 10 maths CBSE

Why is it 530 pm in india when it is 1200 afternoon class 10 social science CBSE

What is deficiency disease class 10 biology CBSE

