Question

Given, \[{\text{2 - chlorobutane}}\] obtained by chlorination of butane, will be
A) Meso form
B) Racemic form
C) \[{\text{d - form}}\]
D) \[{\text{l - form}}\]

Answer 1

Hint: We need to know that in organic chemistry, hydrocarbons are an important topic. The hydrocarbons are majorly classified as three groups. There are alkane, alkene and alkyne. The alkane means carbon-carbon single bond. The alkene has a carbon-carbon double bond. The alkyne means carbon-carbon having triple bond in the molecule.

Complete answer:
The chlorination of butane by chlorine to give \[{\text{2 - chlorobutane}}\].
The symmetric compound chlorination gives an asymmetric compound.
Butane is symmetric compound chlorination given to \[{\text{2 - chlorobutane}}\] as an asymmetric compound. The product will come in a mixture of \[{\text{d - form}}\] and \[{\text{l - form}}\]. Hence, product in racemic form.
According to the above discussion, we conclude
\[{\text{2 - chlorobutane}}\] obtained by chlorination of butane, will be Racemic form

Hence, Option A is not correct, because \[{\text{2 - chlorobutane}}\] obtained by chlorination of butane, will not be in Meso form.
Option B is correct, because \[{\text{2 - chlorobutane}}\] obtained by chlorination of butane, will be a racemic form.
Option C is not correct, because \[{\text{2 - chlorobutane}}\] obtained by chlorination of butane will be not only \[{\text{d - form}}\].
Option C is not correct, because \[{\text{2 - chlorobutane}}\] obtained by chlorination of butane will be not only \[{\text{l - form}}\].

Note:
We have to know the conversion of one type of hydrocarbon to another hydrocarbon by oxidation and reduction. The oxidation of alkane to give alkene. The oxidation of alkene to give alkyne. The reduction of alkyne to give alkene. The reduction of alkene to give alkane. It has some general formulas. The general formula of alkane is \[{{\text{C}}_{\text{n}}}{{\text{H}}_{{\text{2n + 2}}}}\]. The general formula of alkene is \[{{\text{C}}_{\text{n}}}{{\text{H}}_{{\text{2n}}}}\]. The general formula of alkyne is \[{{\text{C}}_{\text{n}}}{{\text{H}}_{{\text{2n - 2}}}}\]. The oxidation means the addition of oxygen or removal of hydrogen or the loss of electrons in the reactant in chemical reaction. The reduction means the removal of hydrogen or the addition of oxygen or the gain of electrons in the chemical reaction.