Give the formula of a compound in which carbon exhibit an oxidation state of:
A) \[ + 4\]
B) $ + 2$
C) $ - 4$
Answer
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Hint: We know that Carbon compounds are characterized as synthetic substances containing carbon. More mixtures of carbon exist than some other synthetic component with the exception of hydrogen. Natural carbon compounds are undeniably more varied than inorganic carbon compounds. Overall obligations of carbon with different components are covalent bonds. Carbon is tetravalent however carbon free revolutionaries and carbenes happen as fleeting intermediates. Particles of carbon are carbocations and carbanions are additionally fleeting. A significant carbon property is catenation as the capacity to frame long carbon chains and rings.
Complete answer:
A) The carbon compound which has $ + 4$ oxidation state is carbon tetrachloride.
Carbon tetrachloride, likewise referred to by numerous different names, for example, tetrachloromethane is a natural compound with the synthetic equation \[CC{l_4}\]. This compound is regularly named a polyhalogenated natural compound since it comprises a carbon iota which is joined to more than one halide utilitarian gathering. Under standard conditions for temperature and pressing factor, \[CC{l_4}\] exists as a drab fluid which radiates an extremely sweet scent.
B) The carbon compound which has $ + 2$ oxidation state is carbon monoxide.
Carbon monoxide (substance equation\[CO\] ) is a boring, scentless, boring, combustible gas that is somewhat less thick than air. Carbon monoxide comprises one carbon molecule and one oxygen particle. It is the least complex atom of the oxocarbon family.
C) The carbon compound which has $ - 4$ oxidation state is methane.
We know that methane is a synthetic compound with the substance recipe \[C{H_4}\] . It is a gathering \[14\] hydride and the easiest alkane, and is the primary constituent of gaseous petrol. The general plenitude of methane on Earth makes it a monetarily alluring fuel, in spite of the fact that catching and putting away it presents specialized difficulties because of its vaporous state under typical conditions for temperature and pressing factor.
Note:
We must have to know that the oxidation state, now and again alluded to as oxidation number, portrays the level of oxidation (loss of electrons) of a molecule in a synthetic compound. Adroitly, the oxidation state, which might be positive, negative or zero, is the speculative charge that a molecule would have if all bonds to ions of various components were \[100\% \] ionic, with no covalent segment. This is never precisely valid for genuine bonds.
Complete answer:
A) The carbon compound which has $ + 4$ oxidation state is carbon tetrachloride.
Carbon tetrachloride, likewise referred to by numerous different names, for example, tetrachloromethane is a natural compound with the synthetic equation \[CC{l_4}\]. This compound is regularly named a polyhalogenated natural compound since it comprises a carbon iota which is joined to more than one halide utilitarian gathering. Under standard conditions for temperature and pressing factor, \[CC{l_4}\] exists as a drab fluid which radiates an extremely sweet scent.
B) The carbon compound which has $ + 2$ oxidation state is carbon monoxide.
Carbon monoxide (substance equation\[CO\] ) is a boring, scentless, boring, combustible gas that is somewhat less thick than air. Carbon monoxide comprises one carbon molecule and one oxygen particle. It is the least complex atom of the oxocarbon family.
C) The carbon compound which has $ - 4$ oxidation state is methane.
We know that methane is a synthetic compound with the substance recipe \[C{H_4}\] . It is a gathering \[14\] hydride and the easiest alkane, and is the primary constituent of gaseous petrol. The general plenitude of methane on Earth makes it a monetarily alluring fuel, in spite of the fact that catching and putting away it presents specialized difficulties because of its vaporous state under typical conditions for temperature and pressing factor.
Note:
We must have to know that the oxidation state, now and again alluded to as oxidation number, portrays the level of oxidation (loss of electrons) of a molecule in a synthetic compound. Adroitly, the oxidation state, which might be positive, negative or zero, is the speculative charge that a molecule would have if all bonds to ions of various components were \[100\% \] ionic, with no covalent segment. This is never precisely valid for genuine bonds.
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