Question

Give balanced chemical equation for the following conversion A, B and C:
$Fe\xrightarrow{A}FeC{{l}_{3}}\xrightarrow{B}FeC{{O}_{3}}\xrightarrow{C}Fe{{(N{{O}_{3}})}_{2}}$

Answer 1

Hint:A balanced chemical equation consist of the same number of moles of the reactants as well as the products. Conversions of chemical compounds take place by removing or replacing various atoms of a compound. Various reagents carry out conversions.

Complete step-by-step answer:We have been given a chemical equation, where iron, Fe is the starting element for the conversion reactions that happen in the presence of A, B, and C. Iron, Fe is first converted into ferric chloride, $FeC{{l}_{3}}$, then this ferric chloride is converted to iron carbonate, which is then converted into iron (III) nitrate.
The series of reactions suggests that iron first reacts with a chlorine molecule to yield ferric chloride, then this ferric chloride is treated with a reactive compound containing carbonate (particularly a base, sodium carbonate), this then reacts with a strong compound containing nitrogen to yield iron (III) nitrate in the last step.
So, first reaction will be as follows:
\[2Fe+3C{{l}_{2}}\to 2FeC{{l}_{3}}\], so A = $C{{l}_{2}}$
The second reaction sequence will be:
$FeC{{l}_{3}}+N{{a}_{2}}C{{O}_{3}}\to FeC{{O}_{3}}$ , B = $N{{a}_{2}}C{{O}_{3}}$
The last reaction step is:
$FeC{{O}_{3}}+2HN{{O}_{3}}\to Fe{{(N{{O}_{3}})}_{2}}+{{H}_{2}}O+C{{O}_{2}}$ , C = $HN{{O}_{3}}$
So, the reaction sequence is as:
$Fe\xrightarrow{C{{l}_{2}}}FeC{{l}_{3}}\xrightarrow{N{{a}_{2}}C{{O}_{3}}}FeC{{O}_{3}}\xrightarrow{HN{{O}_{3}}}Fe{{(N{{O}_{3}})}_{2}}$
Hence, A is chlorine, B is sodium carbonate, and C is nitric acid.

Note:Ferric chloride, when treated with baking soda, which is sodium bicarbonate, then ferric chloride gets neutralized and carbon dioxide gas is released. Also, the reaction of ferric chloride with sodium carbonate in presence of water will yield ferric hydroxide. The reaction is:$FeC{{l}_{3}}+N{{a}_{2}}C{{O}_{3}}+{{H}_{2}}O\to Fe{{(OH)}_{3}}+NaCl+C{{O}_{2}}$