
Give an example of two irrational numbers whose sum and product both are rational.
Answer
576.9k+ views
Hint: Here, we need to know that rational numbers are those numbers that can be written into the form of \[\dfrac{p}{q}\] where \[p\] and \[q\] are integers. But irrational numbers are those which can not be written in the form of \[\dfrac{p}{q}\] . Below are the examples for both:
Rational number: \[\dfrac{1}{2}\], \[\dfrac{4}{5}\]…. etc.
Irrational number: \[\sqrt 3 \] , \[\sqrt 2 \] …. etc.
Complete step-by-step answer:
Step 1: Let's take two irrational numbers \[\sqrt 3 \] and \[ - \sqrt 3 \].
Step 2: Now, we will find the sum of these two irrational numbers as shown below:
\[{\text{Sum}} = \sqrt 3 + \left( { - \sqrt 3 } \right)\]
By opening the brackets into the RHS side of the above expression \[{\text{Sum}} = \sqrt 3 + \left( { - \sqrt 3 } \right)\], we get:
\[ \Rightarrow {\text{Sum}} = \sqrt 3 - \sqrt 3 \] ………….. (1)
By subtracting into the RHS side of the above expression (1), we get:
\[ \Rightarrow {\text{Sum}} = 0\] , which is a rational number.
Step 3: Now, we will calculate the product of these two irrational numbers \[\sqrt 3 \] and \[ - \sqrt 3 \] as shown below:
\[{\text{Product}} = \sqrt 3 \times \left( { - \sqrt 3 } \right)\]
By opening the brackets into the RHS side of the above expression \[{\text{Product}} = \sqrt 3 \times \left( { - \sqrt 3 } \right)\], we get:
\[ \Rightarrow {\text{Product}} = \sqrt 3 \times - \sqrt 3 \] ……….. (2)
By doing multiplication into the RHS side of the above expression (2), we get:
\[ \Rightarrow {\text{Product}} = - 3\] , which is again a rational number.
So, we can see that the sum and product of two irrational numbers can also be equal to a rational number.
The above example of two irrational numbers \[\sqrt 3 \] and \[ - \sqrt 3 \] proved that sum and product of two irrational numbers can also be equal to a rational number.
Note: Students needs to remember some important points about rational and irrational numbers as below:
The Sum of any two rational numbers is equal to a rational number.
The product of any two rational numbers equals a rational number.
The sum of a rational number with an irrational number is an irrational number.
The product of a rational number with an irrational number is an irrational number.
The sum of two irrational numbers is not always irrational.
The product of two irrational numbers is not always irrational.
Rational number: \[\dfrac{1}{2}\], \[\dfrac{4}{5}\]…. etc.
Irrational number: \[\sqrt 3 \] , \[\sqrt 2 \] …. etc.
Complete step-by-step answer:
Step 1: Let's take two irrational numbers \[\sqrt 3 \] and \[ - \sqrt 3 \].
Step 2: Now, we will find the sum of these two irrational numbers as shown below:
\[{\text{Sum}} = \sqrt 3 + \left( { - \sqrt 3 } \right)\]
By opening the brackets into the RHS side of the above expression \[{\text{Sum}} = \sqrt 3 + \left( { - \sqrt 3 } \right)\], we get:
\[ \Rightarrow {\text{Sum}} = \sqrt 3 - \sqrt 3 \] ………….. (1)
By subtracting into the RHS side of the above expression (1), we get:
\[ \Rightarrow {\text{Sum}} = 0\] , which is a rational number.
Step 3: Now, we will calculate the product of these two irrational numbers \[\sqrt 3 \] and \[ - \sqrt 3 \] as shown below:
\[{\text{Product}} = \sqrt 3 \times \left( { - \sqrt 3 } \right)\]
By opening the brackets into the RHS side of the above expression \[{\text{Product}} = \sqrt 3 \times \left( { - \sqrt 3 } \right)\], we get:
\[ \Rightarrow {\text{Product}} = \sqrt 3 \times - \sqrt 3 \] ……….. (2)
By doing multiplication into the RHS side of the above expression (2), we get:
\[ \Rightarrow {\text{Product}} = - 3\] , which is again a rational number.
So, we can see that the sum and product of two irrational numbers can also be equal to a rational number.
The above example of two irrational numbers \[\sqrt 3 \] and \[ - \sqrt 3 \] proved that sum and product of two irrational numbers can also be equal to a rational number.
Note: Students needs to remember some important points about rational and irrational numbers as below:
The Sum of any two rational numbers is equal to a rational number.
The product of any two rational numbers equals a rational number.
The sum of a rational number with an irrational number is an irrational number.
The product of a rational number with an irrational number is an irrational number.
The sum of two irrational numbers is not always irrational.
The product of two irrational numbers is not always irrational.
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