Question

Give an equation each to how the following properties of sulphuric acid: As a non-volatile acid.

Answer 1

Hint: As we know that sulphuric acid is an acidic chemical compound with the formula ${H_2}S{O_4}$. We know that it is widely used in the industries. It is also known as the king of chemicals. It is also known as the oil of vitriol. We know that it is an odourless, colourless and viscous liquid which is soluble in water and the preparation of sulphuric acid generally involves a highly exothermic process.

Complete step by step answer:
We know that one of the many properties of sulphuric acid is that it is a non- volatile acid. Sulphuric acid has high boiling points and this is why it is used in the preparation of volatile acids such as Hydrochloric acid i.e. $HCl$, $HN{O_3}$ and acetic acid from their salts.
It displaces the volatile acid from its salt as: $NaCl + {H_2}S{O_4}\xrightarrow{{ < {{200}^ \circ }C}}NaHS{O_4} + HCl$.
Hence the equation of sulphuric acid as a non-volatile acid is $NaCl + {H_2}S{O_4}\xrightarrow{{ < {{200}^ \circ }C}}NaHS{O_4} + HCl$.

Note: We should note that conc. ${H_2}S{O_4}$ is used in the above chemical equation. We should also know that the chemical name of ${H_2}S{O_4}$is hydrogen sulphate or di-hydrogen sulphate. It contains two atoms of hydrogen, one atom of sulphur and four atoms of oxygen. It has an atomicity of seven.