Question

Fusion of $AgCl$ with $N{a_2}C{O_3}$ gives:
A.$A{g_2}C{O_3}$
B.Silver carbide
C.$Ag$
D.$A{g_2}$

Answer 1

Hint: In the above given reaction silver chloride when reacted with sodium carbonate produces silver, carbon dioxide, sodium chloride and oxygen. Silver carbonate isn’t formed because on heating it readily decomposes to silver carbon dioxide and oxygen.

Complete answer:
In the above given reaction, we are asked what will be the products of the reaction when silver chloride reacts with sodium carbonate.
Now sodium chloride has silver and chlorine while sodium carbonate has sodium, carbon and oxygen. Now the possible compounds which can form after displacement are silver carbonate and sodium chloride. Now sodium chloride is a very stable compound so it will be formed. Silver carbonate is a very unstable compound which during the reaction due to the heat provided and heat produced would further dissociate into silver, carbon dioxide and oxygen. Now carbon dioxide and oxygen will readily blow away from the final products.
The reaction would be something as follows: -
$2N{a_2}C{O_3} + 4AgCl \to 4Ag + 2C{O_2} + 4NaCl + {O_2}$
The above given reaction states that two moles of sodium carbonate react with four moles of sodium chloride to form four moles of silver, two moles of carbon dioxide, four moles of sodium chloride and one mole of oxygen.
By watching the options, we can say silver carbide won't form and silver doesn’t dimerise therefore $A{g_2}$ also won’t exist, while the first option $A{g_2}C{O_3}$ is an unstable compound which dissociates readily.
Fusion of $AgCl$ with $N{a_2}C{O_3}$ gives $Ag$.

Note:
Silver is a relatively soft, shiny metal. It tarnishes slowly in air as sulphur compounds react with the surface forming black silver sulphide. Silver bromide and iodide were important in the history of photography, because of their sensitivity to light.