
From Venn diagram show that $n\left( A\cup B \right)+n\left( A\cap B \right)=n\left( A \right)+n\left( B \right)$.
Answer
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Hint: In this question we have been given with a Venn diagram and using the Venn diagram we have to show that $n\left( A\cup B \right)+n\left( A\cap B \right)=n\left( A \right)+n\left( B \right)$. We will first write all the sets which include the intersection and union set of the given sets $A$ and $B$. We will then consider the left-hand side of the expression and find its value and then consider the right-hand side and find its value and check whether the condition holds true.
Complete step by step answer:
We can see from the Venn diagram that:
$\Rightarrow A=\left\{ a,b,c,d \right\}$
$\Rightarrow B=\left\{ a,b,e,f,g \right\}$
Therefore, we get:
$\Rightarrow n\left( A \right)=4$
$\Rightarrow n\left( B \right)=5$
The union set which is represented as $A\cup B$ represents the set of all the distinct elements that are present in the sets $A$ or $B$. We have the intersection as:
$\Rightarrow A\cup B=\left\{ a,b,c,d,e,f,g \right\}$
Therefore, we have:
$\Rightarrow n\left( A\cup B \right)=7$
The intersection set which is represented as $A\cap B$ represents the set of all the distinct elements that are present in the both sets $A$ and $B$. We have the intersection as:
$\Rightarrow A\cap B=\left\{ a,b \right\}$
Therefore, we have:
$\Rightarrow n\left( A\cap B \right)=2$
Now we have to prove that $n\left( A\cup B \right)+n\left( A\cap B \right)=n\left( A \right)+n\left( B \right)$.
Consider the left-hand side of the expression, we have:
$\Rightarrow n\left( A\cup B \right)+n\left( A\cap B \right)$
On substituting the values, we get:
$\Rightarrow 7+2$
On simplifying, we get:
$\Rightarrow 9$, which is the value of the left-hand side.
Consider the right-hand side of the expression, we have:
$\Rightarrow n\left( A \right)+n\left( B \right)$
On substituting the values, we get:
$\Rightarrow 4+5$
On simplifying, we get:
$\Rightarrow 9$, which is the value of the right-hand side.
Since the values of both the sides are the same the expression is correct, hence proved.
Note: It is to be remembered that the $n\left( P \right)$ represents the number of elements present in the set. A Venn diagram is a good method to simplify set problems such that they can be visualized. The various properties of Venn diagrams should be remembered to solve these types of questions.
Complete step by step answer:
We can see from the Venn diagram that:
$\Rightarrow A=\left\{ a,b,c,d \right\}$
$\Rightarrow B=\left\{ a,b,e,f,g \right\}$
Therefore, we get:
$\Rightarrow n\left( A \right)=4$
$\Rightarrow n\left( B \right)=5$
The union set which is represented as $A\cup B$ represents the set of all the distinct elements that are present in the sets $A$ or $B$. We have the intersection as:
$\Rightarrow A\cup B=\left\{ a,b,c,d,e,f,g \right\}$
Therefore, we have:
$\Rightarrow n\left( A\cup B \right)=7$
The intersection set which is represented as $A\cap B$ represents the set of all the distinct elements that are present in the both sets $A$ and $B$. We have the intersection as:
$\Rightarrow A\cap B=\left\{ a,b \right\}$
Therefore, we have:
$\Rightarrow n\left( A\cap B \right)=2$
Now we have to prove that $n\left( A\cup B \right)+n\left( A\cap B \right)=n\left( A \right)+n\left( B \right)$.
Consider the left-hand side of the expression, we have:
$\Rightarrow n\left( A\cup B \right)+n\left( A\cap B \right)$
On substituting the values, we get:
$\Rightarrow 7+2$
On simplifying, we get:
$\Rightarrow 9$, which is the value of the left-hand side.
Consider the right-hand side of the expression, we have:
$\Rightarrow n\left( A \right)+n\left( B \right)$
On substituting the values, we get:
$\Rightarrow 4+5$
On simplifying, we get:
$\Rightarrow 9$, which is the value of the right-hand side.
Since the values of both the sides are the same the expression is correct, hence proved.
Note: It is to be remembered that the $n\left( P \right)$ represents the number of elements present in the set. A Venn diagram is a good method to simplify set problems such that they can be visualized. The various properties of Venn diagrams should be remembered to solve these types of questions.
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