
From the information given, answer the following question
1) A painter knows Hindi.
2) A farmer, an advocate and a teacher can speak English fluently.
3) Except for the teacher, the other three know Gujarati.
4) Out of Marathi and Hindi, the advocate and the farmer speak only Marathi, but the teacher can speak both languages.
Who knows Marathi as well as Gujarati?
A) Painter and the advocate
B) The farmer and the teacher
C) The advocate and the farmer
D) The teacher and the painter
Answer
555.3k+ views
Hint:
We can consider people who know each language as a set. Then we can add elements to the sets by reading the given information one by one. Then we can take the intersection of the two sets that we need to find. Then the elements in the intersection will be the required answer.
Complete step by step solution:
Let H be the set of people who knows Hindi,
E be the set of people who knows English
G be the set of people who knows Gujarati and
M be the set of people who know Marathi.
Now we can add elements to the set from the given information.
It is given that the painter knows Hindi. So we can add the painter to the set H.
$ \Rightarrow H = \left\{ {{\text{painter}}} \right\}$
Then it is given that a farmer, an advocate and a teacher can speak English fluently. So, we can add them to the set E.
\[ \Rightarrow E = \left\{ {{\text{advocate,teacher,farmer}}} \right\}\]
It is given except for the teacher, the other three know Gujarati. So we can add them to G.
\[ \Rightarrow G = \left\{ {{\text{advocate, painter, farmer}}} \right\}\]
Then we have, out of Marathi and Hindi, the advocate and the farmer speak only Marathi, but the teacher can speak both languages. So, we can add all of them to set M and the teacher to set H.
\[ \Rightarrow M = \left\{ {{\text{advocate, teacher, farmer}}} \right\}\]
\[ \Rightarrow H = \left\{ {{\text{painter, teacher}}} \right\}\].
Now we need to find people who know both Marathi and Gujarati. So, we can take their intersection. We know that intersection of 2 sets gives the elements that contained in both the sets.
\[ \Rightarrow M \cap G = \left\{ {{\text{advocate, farmer}}} \right\}\]
As the intersection contains only the advocate and the farmer, only they know both Marathi and Gujarati.
So, the correct answer is option C which is the advocate and the farmer.
Note:
Alternate method to solve this problem is by eliminating the options,
Consider option A, Painter and advocate.
From condition (4), only the farmer, advocate and teacher know Marathi. As painters don’t know Marathi, option A can be rejected.
Consider B, farmer and teacher.
It is clear from condition 3 that the teacher doesn't know Guajarati. So, B can’t be the answer.
Consider option C, advocate and farmer.
From conditions (3) and (4), we can say that both of them know both Marathi and Gujarati.
So, option C can be the correct answer.
Consider option D, farmer and teacher.
It is clear from condition 3 that the teacher doesn't know Guajarati. So, D can’t be the answer.
Therefore, the correct answer is option C which is the advocate and the farmer.
We can consider people who know each language as a set. Then we can add elements to the sets by reading the given information one by one. Then we can take the intersection of the two sets that we need to find. Then the elements in the intersection will be the required answer.
Complete step by step solution:
Let H be the set of people who knows Hindi,
E be the set of people who knows English
G be the set of people who knows Gujarati and
M be the set of people who know Marathi.
Now we can add elements to the set from the given information.
It is given that the painter knows Hindi. So we can add the painter to the set H.
$ \Rightarrow H = \left\{ {{\text{painter}}} \right\}$
Then it is given that a farmer, an advocate and a teacher can speak English fluently. So, we can add them to the set E.
\[ \Rightarrow E = \left\{ {{\text{advocate,teacher,farmer}}} \right\}\]
It is given except for the teacher, the other three know Gujarati. So we can add them to G.
\[ \Rightarrow G = \left\{ {{\text{advocate, painter, farmer}}} \right\}\]
Then we have, out of Marathi and Hindi, the advocate and the farmer speak only Marathi, but the teacher can speak both languages. So, we can add all of them to set M and the teacher to set H.
\[ \Rightarrow M = \left\{ {{\text{advocate, teacher, farmer}}} \right\}\]
\[ \Rightarrow H = \left\{ {{\text{painter, teacher}}} \right\}\].
Now we need to find people who know both Marathi and Gujarati. So, we can take their intersection. We know that intersection of 2 sets gives the elements that contained in both the sets.
\[ \Rightarrow M \cap G = \left\{ {{\text{advocate, farmer}}} \right\}\]
As the intersection contains only the advocate and the farmer, only they know both Marathi and Gujarati.
So, the correct answer is option C which is the advocate and the farmer.
Note:
Alternate method to solve this problem is by eliminating the options,
Consider option A, Painter and advocate.
From condition (4), only the farmer, advocate and teacher know Marathi. As painters don’t know Marathi, option A can be rejected.
Consider B, farmer and teacher.
It is clear from condition 3 that the teacher doesn't know Guajarati. So, B can’t be the answer.
Consider option C, advocate and farmer.
From conditions (3) and (4), we can say that both of them know both Marathi and Gujarati.
So, option C can be the correct answer.
Consider option D, farmer and teacher.
It is clear from condition 3 that the teacher doesn't know Guajarati. So, D can’t be the answer.
Therefore, the correct answer is option C which is the advocate and the farmer.
Recently Updated Pages
Master Class 11 Chemistry: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

If overrightarrow a overrightarrow b overrightarrow class 12 maths CBSE

If a b and c are unit coplanar vectors then left 2a class 12 maths CBSE

Trending doubts
In what year Guru Nanak Dev ji was born A15 April 1469 class 11 social science CBSE

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

10 examples of friction in our daily life

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

