Question

From the given Chemical Reaction Identify (A) and (B)
(i). \[Ba{{C}_{2}}+{{N}_{2}}\xrightarrow{\Delta }\left( B \right)\]
(ii). \[Ca{{C}_{2}}+{{N}_{2}}\xrightarrow{\Delta }\left( A \right)\]
A) \[A:Ca\left( N=C=N \right);\text{ }B:Ba{{(C\equiv N)}_{2}}\]
B) \[A:Ca\left( N=C=N \right)\text{; B}:B{{a}_{2}}{{\left( C\equiv N \right)}_{4}}\]
C) \[A:Ca{{\left( N=\text{ }C=\text{ }N \right)}_{2}};\text{ }B:Ba{{\left( C\equiv N \right)}_{2}}\]
D) \[A:Ca{{\left( N=C=N \right)}_{2}};\text{ }B:B{{a}_{2}}{{\left( C\equiv N \right)}_{4}}\]

Answer 1

Hint: The Following reaction can be stated as Inorganic + Metallurgy Reaction and is a part of p block element and dinitrogen since its reaction between Calcium Carbide and Nitrogen and in part two Barium Carbide with Nitrogen.As its Inorganic-Metallurgy reaction the compound will be heated upto $1000{}^\circ C$to $1125{}^\circ C$
Complete step-by-step answer:
i) In the Second reaction when Calcium carbide reacts with nitrogen to produce calcium cyanamide and carbon. Reaction proceeds at a heating a reaction mixture to the temperature of $1000{}^\circ C$
ii) This product formation results in loss of Carbon molecules in Inorganic + Metallurgy reaction. Since the Calcium vacancy is fulfilled, the carbon molecule is lost in heat.

\[Ca{{C}_{2}}+{{N}_{2}}\xrightarrow{\Delta }Ca(N=C=N)\]
Likewise, in \[Ba{{C}_{2}}\] when its heated with ${{N}_{2}}$ its subsequently gives \[Ba{{\left( CN \right)}_{2}}\] with no lose in carbon in reaction.
\[Ba{{C}_{2}}+{{N}_{2}}\xrightarrow{\Delta }Ba(N=C=N)\] or \[Ba{{C}_{2}}+{{N}_{2}}\xrightarrow{\Delta }Ba{{(CN)}_{2}}\]

Therefore, $A$ and $B$ are \[A:Ca\left( N=C=N \right);\text{ }B:Ba{{(C\equiv N)}_{2}}\]

So, option (A) is correct answer \[A:Ca\left( N=C=N \right);\text{ }B:Ba{{(C\equiv N)}_{2}}\]

Additional Information:
-Calcium cyanamide is the inorganic compound with the formula $CaC{{N}_{2}}$and $Ba{{(CN)}_{2}}$
-It is the calcium salt of the cyanamide $C{{N}^{2-2}}$anion.
-This chemical is used as fertilizer and is commercially known as nitrolime.

Note: Here you will find the required reactants, $Ca{{C}_{2}}$forms cyanamide but not $Ba{{C}_{2}}$. Meanwhile the product we got from the second part of reaction, calcium cyanamide is known as nitrolim. The whole process of reaction is one of the reactions of nitrogen fixation.