From 200mg of $C{{O}_{2}}$ ,${{10}^{21}}$ molecules are removed how many moles of $C{{O}_{2}}$ are left?
Answer
588.3k+ views
Hint:
-The number $6.022\times {{10}^{23}}$ is also known as Avogadro’s number. The concept of mole can be used to convert between mass and number of particles.
-Number of moles of any substance is the number of molecules of that substance present per avogadro’s number.
Complete step by step answer:
Here we are given the molar mass of $C{{O}_{2}}$ = \[44{ }g\]
Given mass \[=200mg=0.2g\]
Number of moles = $\dfrac{0.2}{44}=0.0045$
So, applying the formula given below:
$\Rightarrow $ Number of molecules $=$ Avogadro’s number $\times $ number of moles-------(1)
Putting the values of number of moles and Avogadro’s number in the equation (1) we get:
$\Rightarrow $ Number of molecules = ${6}{.022 \times 1}{{{0}}^{{23}}}{\times 0}{.0045}$
$\Rightarrow $ Number of molecules = ${2}{.7 \times 1}{{{0}}^{{21}}}$
As it is given in the question that ${{10}^{21}}$ molecules are removed so the number of molecules that are left are given as;
No of molecules left = ${2}{.7 \times 1}{{{0}}^{{21}}}{- 1}{{{0}}^{{21}}}{= 1}{.7 \times 1}{{{0}}^{{21}}}$
So the number of moles of carbon dioxide that are left = $\dfrac{\text{No of molecules}}{\text{Avogadro's number}}=\dfrac{1.7 \times {{10}^{21}}}{6.022 \times {{10}^{23}}}={2}{.8 \times 1}{{{0}}^{{-3}}}$
We can see that after substituting the number of molecules of carbon dioxide left which we calculated above, and the Avogadro’s number which is a Constant term and is known to us, we found out the number of moles of carbon dioxide. Hence, the number of moles of carbon dioxide left = ${2}{.8 \times 1}{{{0}}^{{-3}}}$ . So this is the required answer.
Note: The concept of mole is important because it allows chemists with subatomic worlds with macro world units and amounts. Basically it provides a bridge between the atom and the macroscopic quantities on which we work in the laboratory. Always apply the formula used above to find the number of molecules and take care of the units of mass always.
-The number $6.022\times {{10}^{23}}$ is also known as Avogadro’s number. The concept of mole can be used to convert between mass and number of particles.
-Number of moles of any substance is the number of molecules of that substance present per avogadro’s number.
Complete step by step answer:
Here we are given the molar mass of $C{{O}_{2}}$ = \[44{ }g\]
Given mass \[=200mg=0.2g\]
Number of moles = $\dfrac{0.2}{44}=0.0045$
So, applying the formula given below:
$\Rightarrow $ Number of molecules $=$ Avogadro’s number $\times $ number of moles-------(1)
Putting the values of number of moles and Avogadro’s number in the equation (1) we get:
$\Rightarrow $ Number of molecules = ${6}{.022 \times 1}{{{0}}^{{23}}}{\times 0}{.0045}$
$\Rightarrow $ Number of molecules = ${2}{.7 \times 1}{{{0}}^{{21}}}$
As it is given in the question that ${{10}^{21}}$ molecules are removed so the number of molecules that are left are given as;
No of molecules left = ${2}{.7 \times 1}{{{0}}^{{21}}}{- 1}{{{0}}^{{21}}}{= 1}{.7 \times 1}{{{0}}^{{21}}}$
So the number of moles of carbon dioxide that are left = $\dfrac{\text{No of molecules}}{\text{Avogadro's number}}=\dfrac{1.7 \times {{10}^{21}}}{6.022 \times {{10}^{23}}}={2}{.8 \times 1}{{{0}}^{{-3}}}$
We can see that after substituting the number of molecules of carbon dioxide left which we calculated above, and the Avogadro’s number which is a Constant term and is known to us, we found out the number of moles of carbon dioxide. Hence, the number of moles of carbon dioxide left = ${2}{.8 \times 1}{{{0}}^{{-3}}}$ . So this is the required answer.
Note: The concept of mole is important because it allows chemists with subatomic worlds with macro world units and amounts. Basically it provides a bridge between the atom and the macroscopic quantities on which we work in the laboratory. Always apply the formula used above to find the number of molecules and take care of the units of mass always.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

What organs are located on the left side of your body class 11 biology CBSE

Which gland is known as mixed gland class 11 biology CBSE

