What is the force of gravity between the earth and mass of 20 kg placed on its surface?
Answer
604.2k+ views
Hint: Use the equation for force of gravity acting on the object. Mass of the object is given in the question and we know the value for g i.e. acceleration due to gravity. Substitute these values in the equation for force of gravity directly and calculate the force of gravity between the earth and mass placed on its surface.
Complete answer:
Given: Mass (m)= 20 kg
The equation for force of gravity acting on the object near the surface of the earth is given by,
$F=mg$ …(1)
Where, m is the mass
g is the acceleration due to gravity
Substituting values in the equation. (1) we get,
$F = 20 \times 9.8$
$\therefore F= 196 N$
Hence, the force of gravity between the earth and mass placed on its surface is 196 N.
Additional Information:
Acceleration due to gravity around the surface is approximately $9.8 {m}/{{s}^{2}}$. As the height from the Earth increases, the acceleration due to gravity changes. As the height increases, acceleration due to gravity decreases. Similarly, as the depth decreases, gravity inside the earth decreases.
Note:
According to Newton’s law of universal gravitation, every mass experiences attractive force due to which they are bound together. This attractive force is experienced by every mass irrespective of its size and it even influences everything. Gravitational force is an attractive force.
Students need to note that the gravitational force or force of gravity between the objects is inversely proportional to the square of the distance between them. As the distance between the objects vary, the attractive force between the objects also vary by multiple factors.
Complete answer:
Given: Mass (m)= 20 kg
The equation for force of gravity acting on the object near the surface of the earth is given by,
$F=mg$ …(1)
Where, m is the mass
g is the acceleration due to gravity
Substituting values in the equation. (1) we get,
$F = 20 \times 9.8$
$\therefore F= 196 N$
Hence, the force of gravity between the earth and mass placed on its surface is 196 N.
Additional Information:
Acceleration due to gravity around the surface is approximately $9.8 {m}/{{s}^{2}}$. As the height from the Earth increases, the acceleration due to gravity changes. As the height increases, acceleration due to gravity decreases. Similarly, as the depth decreases, gravity inside the earth decreases.
Note:
According to Newton’s law of universal gravitation, every mass experiences attractive force due to which they are bound together. This attractive force is experienced by every mass irrespective of its size and it even influences everything. Gravitational force is an attractive force.
Students need to note that the gravitational force or force of gravity between the objects is inversely proportional to the square of the distance between them. As the distance between the objects vary, the attractive force between the objects also vary by multiple factors.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Discuss the various forms of bacteria class 11 biology CBSE

