Question

Force acting on a body is given by $F = (1200 \times {10^5}t)N$. After starting the motion it moves with constant velocity, how much impulse of force is acting on it?

Answer 1

Hint: The relationship between force and velocity for a constant mass is given in the relationship between impulse and momentum. Since the mass is constant during free-weight resistance, a greater impulse will result in a greater velocity.

Formula used:
Provides values of mass and velocity change of an object, to calculate the impulse from the equation
\[J = m\Delta v\] (Impulse = Change in Momentum)
\[\Delta v = 0\] (Because Change in velocity =0)

Complete step-by-step solution:
Impulse working on the body is Zero. The reason for the same is that the body moving with constant velocity has no net force working on it.
Any object with momentum goes to be hard to prevent. To prevent such an object, it's necessary to use a force against its motion for a given period of your time. For an object, the more the momentums, the harder that it's to prevent. Thus, it might require a greater amount of force or an extended amount of your time or both to bring such an object to a halt. As the force acts upon the thing for a given amount of your time, the object's velocity is changed; and hence, the object's momentum is modified.
In a collision, an object experiences a force for a selected amount of your time that leads to a change in momentum. The result of the force acting for the given amount of your time is that the object's mass either accelerates or slows down (or changes direction). The impulse experienced by the thing equals the change in momentum of the thing.


Note: The impulse may be a vector, so a negative impulse means internet force is within the negative direction. Similarly, a positive impulse means internet force is within the positive direction.