For what value of \[x\] , is the matrix \[A\] = \[\left[ {\begin{array}{*{20}{c}}
0&1&{ - 2} \\
{ - 1}&0&3 \\
x&{ - 3}&0
\end{array}} \right]\] a skew symmetric matrix ?
Answer
557.4k+ views
Hint: For a matrix to be skew symmetric the condition which is to be satisfied is \[A = - {A^T}\]. Here \[{A^T}\] denotes the transpose of the matrix \[A\] . Here we know the matrix \[A\] . From this we can calculate \[{A^T}\] and \[ - {A^T}\]. Then putting the value of \[A\] and \[ - {A^T}\] in the above condition we can obtain the value of \[x\] .
FORMULA USED :
For a skew symmetric matrix \[A = - {A^T}\].
Complete answer:We are given that \[A\] = \[\left[ {\begin{array}{*{20}{c}}
0&1&{ - 2} \\
{ - 1}&0&3 \\
x&{ - 3}&0
\end{array}} \right]\] we have to find the value of \[x\] such that the matrix satisfies the condition for the skew symmetric matrix .
We know the condition for the skew symmetric matrix \[A = - {A^T}\]. First we will obtain the value of \[{A^T}\] .
Transpose of a matrix is obtained by interchanging rows and columns of matrix, in other words we find the transpose of a matrix by changing rows to columns and columns to rows .
Every element of the matrix \[A\] can be denoted by \[{a_{ij}}\] where \[i\] denotes row number \[j\] denotes column number . \[{a_{ij}}\] = element of \[{i^{th}}\]row and \[{j^{th}}\] column .
Every element of the matrix \[{A^T}\] can be denoted by \[{a_{ji}}\] .
\[A\] = \[\left[ {\begin{array}{*{20}{c}}
0&1&{ - 2} \\
{ - 1}&0&3 \\
x&{ - 3}&0
\end{array}} \right]\]
By changing rows into column and vice versa we get
\[{A^T}\]= \[\left[ {\begin{array}{*{20}{c}}
0&{ - 1}&x \\
1&0&{ - 3} \\
{ - 2}&3&0
\end{array}} \right]\]
So \[ - {A^T}\]= \[\left[ {\begin{array}{*{20}{c}}
0&1&{ - x} \\
{ - 1}&0&3 \\
2&{ - 3}&0
\end{array}} \right]\]
Putting the values of \[A\] and \[ - {A^T}\] in condition we get
\[\left[ {\begin{array}{*{20}{c}}
0&1&{ - 2} \\
{ - 1}&0&3 \\
x&{ - 3}&0
\end{array}} \right]\]=\[\left[ {\begin{array}{*{20}{c}}
0&1&{ - x} \\
{ - 1}&0&3 \\
2&{ - 3}&0
\end{array}} \right]\]
Now we have to equate the matrix. While equating the matrices we must equate every element in a row of a column with the corresponding value of the other matrix.
\[{a_{13}}\] = element of \[{1^{st}}\]row and \[{3^{rd}}\] column .
\[{a_{31}}\] = element of \[{3^{rd}}\]row and \[{1^{st}}\]column .
Equating \[{a_{13}}\] we get
\[ - x = - 2\]
So \[x = 2\]
Equating \[{a_{31}}\] we get
\[x = 2\]
This is the desired answer .
Therefore for \[x = 2\] matrix \[A\] is a skew symmetric matrix .
Note:
Students should remember while multiplying any constant to a matrix we have multiplied this constant to every element of the matrix . Transpose of the matrix should be obtained carefully . Negative sign in the condition is very important ; without the negative sign the condition will become the condition for the symmetric matrix .
FORMULA USED :
For a skew symmetric matrix \[A = - {A^T}\].
Complete answer:We are given that \[A\] = \[\left[ {\begin{array}{*{20}{c}}
0&1&{ - 2} \\
{ - 1}&0&3 \\
x&{ - 3}&0
\end{array}} \right]\] we have to find the value of \[x\] such that the matrix satisfies the condition for the skew symmetric matrix .
We know the condition for the skew symmetric matrix \[A = - {A^T}\]. First we will obtain the value of \[{A^T}\] .
Transpose of a matrix is obtained by interchanging rows and columns of matrix, in other words we find the transpose of a matrix by changing rows to columns and columns to rows .
Every element of the matrix \[A\] can be denoted by \[{a_{ij}}\] where \[i\] denotes row number \[j\] denotes column number . \[{a_{ij}}\] = element of \[{i^{th}}\]row and \[{j^{th}}\] column .
Every element of the matrix \[{A^T}\] can be denoted by \[{a_{ji}}\] .
\[A\] = \[\left[ {\begin{array}{*{20}{c}}
0&1&{ - 2} \\
{ - 1}&0&3 \\
x&{ - 3}&0
\end{array}} \right]\]
By changing rows into column and vice versa we get
\[{A^T}\]= \[\left[ {\begin{array}{*{20}{c}}
0&{ - 1}&x \\
1&0&{ - 3} \\
{ - 2}&3&0
\end{array}} \right]\]
So \[ - {A^T}\]= \[\left[ {\begin{array}{*{20}{c}}
0&1&{ - x} \\
{ - 1}&0&3 \\
2&{ - 3}&0
\end{array}} \right]\]
Putting the values of \[A\] and \[ - {A^T}\] in condition we get
\[\left[ {\begin{array}{*{20}{c}}
0&1&{ - 2} \\
{ - 1}&0&3 \\
x&{ - 3}&0
\end{array}} \right]\]=\[\left[ {\begin{array}{*{20}{c}}
0&1&{ - x} \\
{ - 1}&0&3 \\
2&{ - 3}&0
\end{array}} \right]\]
Now we have to equate the matrix. While equating the matrices we must equate every element in a row of a column with the corresponding value of the other matrix.
\[{a_{13}}\] = element of \[{1^{st}}\]row and \[{3^{rd}}\] column .
\[{a_{31}}\] = element of \[{3^{rd}}\]row and \[{1^{st}}\]column .
Equating \[{a_{13}}\] we get
\[ - x = - 2\]
So \[x = 2\]
Equating \[{a_{31}}\] we get
\[x = 2\]
This is the desired answer .
Therefore for \[x = 2\] matrix \[A\] is a skew symmetric matrix .
Note:
Students should remember while multiplying any constant to a matrix we have multiplied this constant to every element of the matrix . Transpose of the matrix should be obtained carefully . Negative sign in the condition is very important ; without the negative sign the condition will become the condition for the symmetric matrix .
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

The teeth used for biting and cutting food are called class 11 biology CBSE

Frogs heart when taken out of the body continues to class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

