Question

For formation of 50 seeds, how many minimum meiotic divisions are necessary?
A) 25
B) 50
C) 75
D) 63

Answer 1

Hint: In meiosis, two rounds of cell division accompany DNA replication to create four daughter cells, each of which has 23 chromosomes as the main parent cell. Meiosis I and meiosis II are referred to as the two meiotic divisions.

Complete answer:
In order to halve the chromosome number (diploid to haploid), the first meiotic division divides pairs of homologous chromosomes. Sister chromatids are divided by the second meiotic division

Now, let us find the solution from the options-
-One egg is generated by the meiosis of the mother cell of the egg. Thus, the overall number of seeds is equivalent to the number of female meiotic divisions.
-Each pollen mother cell is also known to be separated by meiosis to create four haploid pollen grains.
-Of these, only one pollen grain is used in fertilization. Therefore, the number of meiotic divisions in a male is equivalent to $\dfrac{1}{4}$ of the overall number of seeds.
-Now, the complete number of divisions = $\dfrac{50}{4}\:+50\:=\:12.5\:+50\:=\:62.5$
-Divisions cannot take place in decimal positions.

Thus, the correct answer is option (D) 63.

Note: The separation is crossed over by genetic material between the paternal and maternal copies within each chromosome, producing unique code variants for each chromosome. After, during fertilization, the haploid cells from a male and female formed by meiosis can combine to form a cell again with two copies of each chromosome, the zygote is formed.