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For every line $ L $ and for every point $ P $ not lying on a given line $ L $ , there exist _________ passing through $ P $ and parallel to $ L $ .
(A) no line
(B) a unique line
(C) two lines
(D) infinitely many lines

Answer
VerifiedVerified
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Hint: Solve this question diagrammatically. Draw a line $ L $ , a point $ P $ , and then check if it is possible to draw a line parallel to $ L $ and passing through $ P $ . If it is possible, then observe, how many such lines can be drawn.

Complete step-by-step answer:
Let us consider any line L and any point P, which is not lying on the line L. Construct a line passing through point P and intersecting the line L at some random point B.
Refer the diagram
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Now, let us say that we draw a line $ m||L $ . Such that, it passes through point P. Then, the line PB will be the transversal line for the lines $ m $ and $ L $ .
Hence, by the property of parallel lines, the corresponding angles formed at P and B, by the two lines, will be the same.
Refer the diagram
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Clearly, by observing the above diagram, we can observe that it is not possible to draw any other line parallel to the line $ L $ , such that it would pass through the point $ P $ and would make the same angle that the line $ PB $ is making with line $ L $ .
Therefore, from the above explanation, we can conclude that, for every line $ L $ and for every point $ P $ not lying on a given line $ L $ , there exists a unique line passing through $ P $ and parallel to $ L $ .
So, the correct answer is “Option B”.

Note: This is a theoretical question. Such questions can be solved by visualizing. Here, the important point to note is that you can always draw only a line passing through a fixed point and making a fixed angle with respect to any other line. You can check this by assuming line $ L $ as X-axis.