
For a particular resonance tube, following are four of the six harmonics below $1000Hz$
$300,{\text{ }}600,\;750,\;and{\text{ }}900Hz$
The two missing harmonics are
(A) $75,{\text{ }}150$
(B) $150,{\text{ 4}}50$
(C) $400,{\text{ 80}}0$
(D) $250,{\text{ 40}}0$
Answer
589.8k+ views
Hint
To solve this question, we need to use the formula of the frequency of the closed organ pipe. Then by finding the H.C.F. of the values of the frequencies given in the question, we can find the missing frequencies.
$\Rightarrow f = \dfrac{{nv}}{{2L}}$, where $f$ is the ${n^{th}}$ harmonic frequency for a closed organ pipe of length $L$ and $n$ is a positive integer.
Complete step by step answer
We know that the ${n^{th}}$ harmonic frequency in a closed organ pipe is given by the relation
$\Rightarrow f = \dfrac{{nv}}{{2L}}$, $n = 1,2,3......$ (1)
By putting different values of $n$, we get the different frequencies.
So, each harmonic is a multiple of the fundamental frequency ${f_0} = \dfrac{v}{{2L}}$
Therefore, from (1), we have
$\Rightarrow f = n{f_0}$ (2)
The frequencies given in the question are of
$300,{\text{ }}600,\;750,\;and{\text{ }}900Hz$
To find the missing frequencies, first we need to find the fundamental frequency ${f_0}$, which the given frequencies are the multiples of.
To find the fundamental frequency, we need to find the H.C.F. of the frequencies given in the question.
So, H.C.F. of $300,{\text{ }}600,\;750,\;and{\text{ }}900 = 150$
Hence, the fundamental frequency, ${f_0} = 150Hz$
From (2) we get
$\Rightarrow f = 150n$
Putting the values of $n$ from $1$ to $6$, we get the six harmonics as follows
$150,{\text{ }}300,{\text{ 450, }}600,\;750,\;and{\text{ }}900Hz$
So, the missing frequencies are $150,{\text{ 450Hz}}$
Hence, the correct answer is option (B); $150,{\text{ 450}}$
Note
If we don’t know the exact formula for the ${n^{th}}$ harmonic frequency, then also we can solve these types of questions. This is because the harmonic frequencies are always a multiple of the corresponding fundamental frequency. So, we just need to find out the value of the H.C.F. of the frequencies given the problem, which will be the fundamental frequency. By putting the different values of $n$, we will get the missing frequencies.
To solve this question, we need to use the formula of the frequency of the closed organ pipe. Then by finding the H.C.F. of the values of the frequencies given in the question, we can find the missing frequencies.
$\Rightarrow f = \dfrac{{nv}}{{2L}}$, where $f$ is the ${n^{th}}$ harmonic frequency for a closed organ pipe of length $L$ and $n$ is a positive integer.
Complete step by step answer
We know that the ${n^{th}}$ harmonic frequency in a closed organ pipe is given by the relation
$\Rightarrow f = \dfrac{{nv}}{{2L}}$, $n = 1,2,3......$ (1)
By putting different values of $n$, we get the different frequencies.
So, each harmonic is a multiple of the fundamental frequency ${f_0} = \dfrac{v}{{2L}}$
Therefore, from (1), we have
$\Rightarrow f = n{f_0}$ (2)
The frequencies given in the question are of
$300,{\text{ }}600,\;750,\;and{\text{ }}900Hz$
To find the missing frequencies, first we need to find the fundamental frequency ${f_0}$, which the given frequencies are the multiples of.
To find the fundamental frequency, we need to find the H.C.F. of the frequencies given in the question.
So, H.C.F. of $300,{\text{ }}600,\;750,\;and{\text{ }}900 = 150$
Hence, the fundamental frequency, ${f_0} = 150Hz$
From (2) we get
$\Rightarrow f = 150n$
Putting the values of $n$ from $1$ to $6$, we get the six harmonics as follows
$150,{\text{ }}300,{\text{ 450, }}600,\;750,\;and{\text{ }}900Hz$
So, the missing frequencies are $150,{\text{ 450Hz}}$
Hence, the correct answer is option (B); $150,{\text{ 450}}$
Note
If we don’t know the exact formula for the ${n^{th}}$ harmonic frequency, then also we can solve these types of questions. This is because the harmonic frequencies are always a multiple of the corresponding fundamental frequency. So, we just need to find out the value of the H.C.F. of the frequencies given the problem, which will be the fundamental frequency. By putting the different values of $n$, we will get the missing frequencies.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Actinoid contraction is more than lanthanoid contraction class 11 chemistry CBSE

The transition element that has lowest enthalpy of class 11 chemistry CBSE

Can anyone list 10 advantages and disadvantages of friction

State the laws of reflection of light

