
For a gaseous reaction \[A\left( g \right)\to \text{Product}\], which one of the following is correct relation among \[\dfrac{dp}{dt},\dfrac{dn}{dt}\] and \[\dfrac{dc}{dt}\]
\[\left( \begin{align}
& \dfrac{dp}{dt}=\text{Rate of relation in atm se}{{\text{c}}^{-1}} \\
& \dfrac{dc}{dt}=\text{Rate of relation in molarity se}{{\text{c}}^{-1}} \\
& \dfrac{dn}{dt}=\text{ Rate of reaction in mol se}{{\text{c}}^{-1}} \\
\end{align} \right)\]
A. \[\dfrac{dc}{dt}=\dfrac{dn}{dt}=\dfrac{-dp}{dt}\]
B. \[\dfrac{-dc}{dt}=\dfrac{1}{v}\dfrac{dn}{dt}=\dfrac{-1}{RT}\dfrac{dp}{dt}\]
C. \[\dfrac{dc}{dt}=\dfrac{v}{RT}\dfrac{dn}{dt}=\dfrac{dp}{dt}\].
D. None of these
Answer
589.8k+ views
Hint: We can solve these type of question by considering the equation of state for an ideal gas which is given as \[PV=nRT\]
We can differentiate the equation with respect to time and find the relation between the quantities which are asked also. Also we must know that
\[\text{Concentration}=\dfrac{\text{Number of moles}}{\text{Volume of gas}}\].
Complete answer:
From the equation of the state which is \[PV=nRT\]
Where P = Pressure exerted by the gas
V = Volume of gas
n = moles of gas
R = universal gas constant
T = Temperature
\[PV=nRT\] (differentiating the equation on both sides we get)
\[\dfrac{dp.V}{dt}=RT.\dfrac{dn}{dt}\]
\[\Rightarrow \dfrac{1}{V}\dfrac{dn}{dt}=\dfrac{1}{RT}\dfrac{dp}{dt}\text{ }...........\text{ }1\]
Now Consider, \[PV=nRT\] or \[P=\dfrac{n}{V}RT\]
Concentration \[=\dfrac{n}{V}=C\]
Substituting this value in as one equation we get, \[P=CRT\]
Differentiating with respect to dt on both side we get,
\[\dfrac{dp}{dt}=\dfrac{dc}{dt}RT\]
\[\dfrac{dc}{dt}=\dfrac{1}{RT}\dfrac{dp}{dt}\]
Hence, the correct relationship between the given value are:
\[\dfrac{-dc}{dt}=\dfrac{-1}{v}\dfrac{dn}{dt}=\dfrac{-1}{RT}\dfrac{dp}{dt}\]
Hence correct option in option B.
Note: In thermodynamics the equation of state is a thermodynamic equation relating state variables which describe the state of matter under a given set of physical conditions, such as pressure volume and temperature or internal energy as and when required.
We can differentiate the equation with respect to time and find the relation between the quantities which are asked also. Also we must know that
\[\text{Concentration}=\dfrac{\text{Number of moles}}{\text{Volume of gas}}\].
Complete answer:
From the equation of the state which is \[PV=nRT\]
Where P = Pressure exerted by the gas
V = Volume of gas
n = moles of gas
R = universal gas constant
T = Temperature
\[PV=nRT\] (differentiating the equation on both sides we get)
\[\dfrac{dp.V}{dt}=RT.\dfrac{dn}{dt}\]
\[\Rightarrow \dfrac{1}{V}\dfrac{dn}{dt}=\dfrac{1}{RT}\dfrac{dp}{dt}\text{ }...........\text{ }1\]
Now Consider, \[PV=nRT\] or \[P=\dfrac{n}{V}RT\]
Concentration \[=\dfrac{n}{V}=C\]
Substituting this value in as one equation we get, \[P=CRT\]
Differentiating with respect to dt on both side we get,
\[\dfrac{dp}{dt}=\dfrac{dc}{dt}RT\]
\[\dfrac{dc}{dt}=\dfrac{1}{RT}\dfrac{dp}{dt}\]
Hence, the correct relationship between the given value are:
\[\dfrac{-dc}{dt}=\dfrac{-1}{v}\dfrac{dn}{dt}=\dfrac{-1}{RT}\dfrac{dp}{dt}\]
Hence correct option in option B.
Note: In thermodynamics the equation of state is a thermodynamic equation relating state variables which describe the state of matter under a given set of physical conditions, such as pressure volume and temperature or internal energy as and when required.
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