
For a certain radioactive substance, it is observed that after\[4\,{\text{h}}\], only \[{\text{6}}{\text{.25% }}\] of the original sample is left undecayed. It follows that
This question has multiple correct options
A. The half-life of the sample is \[1\,{\text{h}}\]
B. The mean life of the sample is \[\dfrac{1}{{{\text{ln}}2}}{\text{h}}\]
C. The decay constant of the sample is \[\ln \left( 2 \right){{\text{h}}^{ - 1}}\]
D. After a further \[4\,{\text{h}}\], the amount of the substance left over would by only \[0.39\% \] of the original amount
Answer
553.2k+ views
Hint: We use the formula of radioactivity and we also use the given information for this solution and solve it accordingly. Tracers are a common radioisotope application.
Complete step by step answer:
We know that,
Law of radioactivity,
\[N = {N_{\text{0}}}{e^{ - \lambda t}}\] …… (1)
Where,
\[\,\lambda \,\] is decay constant.
Let us consider,
\[{N_0} = 100\]
So
\[N = 6.25\]
Here,
\[t = 4\,{\text{h}}\]
Now,
$ 6.25 = 100{e^{ - \lambda \left( 4 \right)}} \\\implies {e^{4\lambda }} = 16 \\\implies 4\lambda = \ln 16 \\\implies \ln {2^4} = 4\ln 2 \\\implies \lambda = \lambda \nu \left( 2 \right){{\text{h}}^{ - 1}} \\ $
Mean life\[ = \dfrac{1}{\lambda } = \dfrac{1}{{\ln 2}}h\]
Half-life, \[t = {t_{1/2}}\],
So,
$N = {N_0}/2 \\\implies {N_0}/2 = {N_0}{e^{ - \lambda {t_{1/2}}}} \\
\implies {e^{\ln 2\left( {{t_{1/2}}} \right)}} = 2 \\ \implies \ln 2\left( {{t_{1/2}}} \right) = \ln 2 \\\implies {t_{1/2}} = 1\,h \\ $
For t = 4h , decay $N_0$ = 6.25
From equation (1)
$ N = 6.25{e^{ - 4\ln 2}} \\$
$N= 0.39 \\$
So, the correct answer is “Option A,B,C&D”.
Additional Information:
Radioactive substance: Atoms that decay naturally are radioactive substances. It can produce alpha, beta and gamma-radiation particles. They cannot be switched off unlike X-ray sources, so it is harder to control them. Gamma radiation emitters are industrial x-rays sources such as iridium \[192\] and can be used for x-raying thick sections of the steel and other metals. These are also used inside protected enclosures but because the sources are not electrically switched off, they are housed in shielded containers. The source is projected from the container through a guiding tube and retracted to the point of use. With radioactive sources, living organisms, diseases, medical instruments and foods are diagnosed and treated, heat and electrical energy is produced and various steps are monitored in every type of industrial process. Tracers are a common radioisotope application.
Note:
Large amounts of exposure to radioactive substances can result in nausea, vibration, hair losing, diarrhea, blood flow, damage to the central nervous system and death. DNA damage is also caused and the risk of cancer is increased, especially in young children and fetuses.
Complete step by step answer:
We know that,
Law of radioactivity,
\[N = {N_{\text{0}}}{e^{ - \lambda t}}\] …… (1)
Where,
\[\,\lambda \,\] is decay constant.
Let us consider,
\[{N_0} = 100\]
So
\[N = 6.25\]
Here,
\[t = 4\,{\text{h}}\]
Now,
$ 6.25 = 100{e^{ - \lambda \left( 4 \right)}} \\\implies {e^{4\lambda }} = 16 \\\implies 4\lambda = \ln 16 \\\implies \ln {2^4} = 4\ln 2 \\\implies \lambda = \lambda \nu \left( 2 \right){{\text{h}}^{ - 1}} \\ $
Mean life\[ = \dfrac{1}{\lambda } = \dfrac{1}{{\ln 2}}h\]
Half-life, \[t = {t_{1/2}}\],
So,
$N = {N_0}/2 \\\implies {N_0}/2 = {N_0}{e^{ - \lambda {t_{1/2}}}} \\
\implies {e^{\ln 2\left( {{t_{1/2}}} \right)}} = 2 \\ \implies \ln 2\left( {{t_{1/2}}} \right) = \ln 2 \\\implies {t_{1/2}} = 1\,h \\ $
For t = 4h , decay $N_0$ = 6.25
From equation (1)
$ N = 6.25{e^{ - 4\ln 2}} \\$
$N= 0.39 \\$
So, the correct answer is “Option A,B,C&D”.
Additional Information:
Radioactive substance: Atoms that decay naturally are radioactive substances. It can produce alpha, beta and gamma-radiation particles. They cannot be switched off unlike X-ray sources, so it is harder to control them. Gamma radiation emitters are industrial x-rays sources such as iridium \[192\] and can be used for x-raying thick sections of the steel and other metals. These are also used inside protected enclosures but because the sources are not electrically switched off, they are housed in shielded containers. The source is projected from the container through a guiding tube and retracted to the point of use. With radioactive sources, living organisms, diseases, medical instruments and foods are diagnosed and treated, heat and electrical energy is produced and various steps are monitored in every type of industrial process. Tracers are a common radioisotope application.
Note:
Large amounts of exposure to radioactive substances can result in nausea, vibration, hair losing, diarrhea, blood flow, damage to the central nervous system and death. DNA damage is also caused and the risk of cancer is increased, especially in young children and fetuses.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

Which animal has three hearts class 11 biology CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

