For a certain light there are $2 \times {10^3}$ waves in 1.5 mm in air. The wavelength of light is:
A. 750 nm
B. \[75\;{\rm{A}}^\circ \]
C. \[750\;{\rm{A}}^\circ \]
D. \[7.5 \times {10^{ - 7}}\;{\rm{A}}^\circ \]
Answer
630k+ views
Hint: The wavelength is the number distance between the two crests or two troughs in any frequency. The wavelength is taken as mm, cm, m as the units to calculate. The frequency is defined as vibrations that form in waves per second time.
Complete step by step solution
Given:
The number of waves in a certain light is $n = 2 \times {10^3}$.
The length of the air is
\[\begin{array}{c}
l = 1.5\;{\rm{mm}}\\
{\rm{ = 1}}{\rm{.5}} \times \dfrac{{1\,{\rm{m}}}}{{1000\,{\rm{mm}}}}\\
= {\rm{1}}{\rm{.5}} \times {10^{ - 3}}\,{\rm{m}}
\end{array}\].
The equation to find the wavelength of the light is,
\[\lambda = \dfrac{l}{n}\]
It means the wavelength of the light is defined as the ratio of the length of the waves in the air to the number of waves in a certain light.
Substitute the values in the above equation.
\[\begin{array}{c}
\lambda = \dfrac{l}{n}\\
= \dfrac{{1.5 \times {{10}^{ - 3}}\,m}}{{2 \times {{10}^3}}}\\
= 7.5 \times {10^{ - 7}}\,{\rm{m}}\\
= \left( {7.5 \times {{10}^{ - 7}}\,{\rm{m}}} \right)\left( {\dfrac{{1\;{\rm{nm}}}}{{{{10}^{ - 9}}\;{\rm{m}}}}} \right)\\
= 750\;{\rm{nm}}
\end{array}\]
Therefore, the wavelength is \[750\;\,{\rm{nm}}\] that means the option (a) is correct.
Note: Before substituting the values, be sure the units are according to the requirement. The conversion of millimeters to the meters can be done by dividing 1000.
Complete step by step solution
Given:
The number of waves in a certain light is $n = 2 \times {10^3}$.
The length of the air is
\[\begin{array}{c}
l = 1.5\;{\rm{mm}}\\
{\rm{ = 1}}{\rm{.5}} \times \dfrac{{1\,{\rm{m}}}}{{1000\,{\rm{mm}}}}\\
= {\rm{1}}{\rm{.5}} \times {10^{ - 3}}\,{\rm{m}}
\end{array}\].
The equation to find the wavelength of the light is,
\[\lambda = \dfrac{l}{n}\]
It means the wavelength of the light is defined as the ratio of the length of the waves in the air to the number of waves in a certain light.
Substitute the values in the above equation.
\[\begin{array}{c}
\lambda = \dfrac{l}{n}\\
= \dfrac{{1.5 \times {{10}^{ - 3}}\,m}}{{2 \times {{10}^3}}}\\
= 7.5 \times {10^{ - 7}}\,{\rm{m}}\\
= \left( {7.5 \times {{10}^{ - 7}}\,{\rm{m}}} \right)\left( {\dfrac{{1\;{\rm{nm}}}}{{{{10}^{ - 9}}\;{\rm{m}}}}} \right)\\
= 750\;{\rm{nm}}
\end{array}\]
Therefore, the wavelength is \[750\;\,{\rm{nm}}\] that means the option (a) is correct.
Note: Before substituting the values, be sure the units are according to the requirement. The conversion of millimeters to the meters can be done by dividing 1000.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

What is the Total Duration of Football Match?

The shortest day of the year in India

In which year voting age was reduced from 21 to 18?

10 examples of evaporation in daily life with explanations

What planets have no moons Which one has only one moon class 10 physics CBSE

