
For a certain light there are $2 \times {10^3}$ waves in 1.5 mm in air. The wavelength of light is:
A. 750 nm
B. \[75\;{\rm{A}}^\circ \]
C. \[750\;{\rm{A}}^\circ \]
D. \[7.5 \times {10^{ - 7}}\;{\rm{A}}^\circ \]
Answer
574.8k+ views
Hint: The wavelength is the number distance between the two crests or two troughs in any frequency. The wavelength is taken as mm, cm, m as the units to calculate. The frequency is defined as vibrations that form in waves per second time.
Complete step by step solution
Given:
The number of waves in a certain light is $n = 2 \times {10^3}$.
The length of the air is
\[\begin{array}{c}
l = 1.5\;{\rm{mm}}\\
{\rm{ = 1}}{\rm{.5}} \times \dfrac{{1\,{\rm{m}}}}{{1000\,{\rm{mm}}}}\\
= {\rm{1}}{\rm{.5}} \times {10^{ - 3}}\,{\rm{m}}
\end{array}\].
The equation to find the wavelength of the light is,
\[\lambda = \dfrac{l}{n}\]
It means the wavelength of the light is defined as the ratio of the length of the waves in the air to the number of waves in a certain light.
Substitute the values in the above equation.
\[\begin{array}{c}
\lambda = \dfrac{l}{n}\\
= \dfrac{{1.5 \times {{10}^{ - 3}}\,m}}{{2 \times {{10}^3}}}\\
= 7.5 \times {10^{ - 7}}\,{\rm{m}}\\
= \left( {7.5 \times {{10}^{ - 7}}\,{\rm{m}}} \right)\left( {\dfrac{{1\;{\rm{nm}}}}{{{{10}^{ - 9}}\;{\rm{m}}}}} \right)\\
= 750\;{\rm{nm}}
\end{array}\]
Therefore, the wavelength is \[750\;\,{\rm{nm}}\] that means the option (a) is correct.
Note: Before substituting the values, be sure the units are according to the requirement. The conversion of millimeters to the meters can be done by dividing 1000.
Complete step by step solution
Given:
The number of waves in a certain light is $n = 2 \times {10^3}$.
The length of the air is
\[\begin{array}{c}
l = 1.5\;{\rm{mm}}\\
{\rm{ = 1}}{\rm{.5}} \times \dfrac{{1\,{\rm{m}}}}{{1000\,{\rm{mm}}}}\\
= {\rm{1}}{\rm{.5}} \times {10^{ - 3}}\,{\rm{m}}
\end{array}\].
The equation to find the wavelength of the light is,
\[\lambda = \dfrac{l}{n}\]
It means the wavelength of the light is defined as the ratio of the length of the waves in the air to the number of waves in a certain light.
Substitute the values in the above equation.
\[\begin{array}{c}
\lambda = \dfrac{l}{n}\\
= \dfrac{{1.5 \times {{10}^{ - 3}}\,m}}{{2 \times {{10}^3}}}\\
= 7.5 \times {10^{ - 7}}\,{\rm{m}}\\
= \left( {7.5 \times {{10}^{ - 7}}\,{\rm{m}}} \right)\left( {\dfrac{{1\;{\rm{nm}}}}{{{{10}^{ - 9}}\;{\rm{m}}}}} \right)\\
= 750\;{\rm{nm}}
\end{array}\]
Therefore, the wavelength is \[750\;\,{\rm{nm}}\] that means the option (a) is correct.
Note: Before substituting the values, be sure the units are according to the requirement. The conversion of millimeters to the meters can be done by dividing 1000.
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