Question

Find two consecutive natural numbers whose sum is 63 .

Answer 1

Hint: First of all take the consecutive natural numbers as n and n + 1 and then add them and equate it to 63 and then solve the addition equation for n. Then substitute the value of n in n and n + 1.

Complete step-by-step answer:

We have asked to find two consecutive natural numbers. Let us assume the two numbers as a and b. We know that, the natural numbers are in the form of 1, 2, 3, 4……... As we can see from the series of natural numbers, the consecutive natural numbers have a difference of 1 so we can write a as n and b as n + 1.
Now, equating addition of n and n + 1 to 63, we get:
n + (n + 1) = 63
$\Rightarrow $ 2n + 1 = 63
$\Rightarrow $ 2n = 63 – 1
$\Rightarrow $ 2n = 62
$\Rightarrow $ n = 31
From the above expression, we have got the value of n as 31. Now, n is 31 so n + 1 will be 32.
Hence, the two consecutive natural numbers that has been asked in the question is 31 and 32.

Note: There is another way of finding the consecutive natural numbers is to by adding two consecutive natural numbers starting from 1 & 2 then 2 & 3 and do this process until you get the summation equal to 63. Here intuitively, you can see that adding small numbers won’t give 63 so you can start by adding bigger numbers like 10 and 11 and then see when you will get 63. This way you can save your time.