
Find the \[x\] and $y$ intercepts for the line $y = x + 5$.
Answer
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Hint:
The $x$ - intercept and the $y$ - intercept, respectively indicates the points where the line cuts the \[x\] - axis and the $y$- axis respectively.
Complete step by step solution:
To find the $x$ - intercept and the $y$ - intercept, we need to find the points on the \[x\] - axis and the $y$- axis where the line cuts the axes.
To find the $x$ - intercept we need to find the point on the \[x\] - axis, hence the ordinate of this point will be $0$. Therefore to obtain the abscissa of this point i.e. equal to the $x$ - intercept, substitute $y = 0$ in the given equation of the line.
Putting $y = 0$, in $y = x + 5$,
$0 = x + 5$
$ \Rightarrow x + 5 = 0$
$ \Rightarrow x = - 5$
Hence, the $x$ - intercept of the line is $ - 5$.
To find the $y$ - intercept we need to find the point on the \[y\] - axis, hence the abscissa of this point will be $0$. Therefore to obtain the ordinate of this point i.e. equal to the $y$ - intercept, substitute $x = 0$ in the given equation of the line.
Putting $x = 0$, in $y = x + 5$,
$y = 0 + 5$
$ \Rightarrow y = 5$
Hence, the $y$ - intercept of the line is $5$.
Additional information:
The concept of intercept can be visualised from the adjoining graph.
Note:
Since the line given in the question is in the slope intercept form hence, we can also find the $y$ - intercept directly. The line is in the form $y = mx + c$ where $m = $ slope of the line, $c = $ $y$ - intercept. Therefore comparing the equation $y = x + 5$ with the slope-intercept form, the $y$ - intercept is equal to $5$.
The $x$ - intercept and the $y$ - intercept, respectively indicates the points where the line cuts the \[x\] - axis and the $y$- axis respectively.
Complete step by step solution:
To find the $x$ - intercept and the $y$ - intercept, we need to find the points on the \[x\] - axis and the $y$- axis where the line cuts the axes.
To find the $x$ - intercept we need to find the point on the \[x\] - axis, hence the ordinate of this point will be $0$. Therefore to obtain the abscissa of this point i.e. equal to the $x$ - intercept, substitute $y = 0$ in the given equation of the line.
Putting $y = 0$, in $y = x + 5$,
$0 = x + 5$
$ \Rightarrow x + 5 = 0$
$ \Rightarrow x = - 5$
Hence, the $x$ - intercept of the line is $ - 5$.
To find the $y$ - intercept we need to find the point on the \[y\] - axis, hence the abscissa of this point will be $0$. Therefore to obtain the ordinate of this point i.e. equal to the $y$ - intercept, substitute $x = 0$ in the given equation of the line.
Putting $x = 0$, in $y = x + 5$,
$y = 0 + 5$
$ \Rightarrow y = 5$
Hence, the $y$ - intercept of the line is $5$.
Additional information:
The concept of intercept can be visualised from the adjoining graph.
Note:
Since the line given in the question is in the slope intercept form hence, we can also find the $y$ - intercept directly. The line is in the form $y = mx + c$ where $m = $ slope of the line, $c = $ $y$ - intercept. Therefore comparing the equation $y = x + 5$ with the slope-intercept form, the $y$ - intercept is equal to $5$.
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