Find the wrong term in square:
$1,8,27,64,100,125$
A.$8$
B.$27$
C. $64$
D. $100$
Answer
650.7k+ views
Hint: We will see that in the sequence of order all numbers will multiply by three times but one number does not follow the same rule so that will be the wrong answer. By using the formula: Cubes of natural numbers.
Complete step by step solution:
Given sequence is $1,8,27,64,100\,and\,125$
As we know that
${1^3} = 1{\kern 1pt} \times 1 \times 1 = 1$
${2^3} = 2 \times 2 \times 2 = 8$
${3^3} = 3 \times 3 \times 3 = 27$
${4^3} = 4 \times 4 \times 4 = 64$
${10^2} = 10 \times 10 = 100$
${5^3} = 5 \times 5 \times 5 = 125$
So, $100$number will not be the cube of$10$.
Thus, the wrong number is $100$.
Hence, the correct option is $D$
Note: Observe the sequence carefully and find a pattern associated with it and after this find out the odd term in the sequence
Complete step by step solution:
Given sequence is $1,8,27,64,100\,and\,125$
As we know that
${1^3} = 1{\kern 1pt} \times 1 \times 1 = 1$
${2^3} = 2 \times 2 \times 2 = 8$
${3^3} = 3 \times 3 \times 3 = 27$
${4^3} = 4 \times 4 \times 4 = 64$
${10^2} = 10 \times 10 = 100$
${5^3} = 5 \times 5 \times 5 = 125$
So, $100$number will not be the cube of$10$.
Thus, the wrong number is $100$.
Hence, the correct option is $D$
Note: Observe the sequence carefully and find a pattern associated with it and after this find out the odd term in the sequence
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