Question

Find the weight of 28 bricks if 17 bricks weigh 102 Kg.

Answer 1

Hint: We use the unitary system to find the weight of 1 brick from the weight of 17 bricks being 102. Then we multiply with 28 to find the weight of those bricks.

Complete step-by-step answer:
It is given that 17 bricks weigh 102 Kg. We use a unitary system to find the weight of 1 brick.
We divide 102 with 17 to find the weight of 1 brick.
So, the weight will be $ \dfrac{102}{17} $ Kg.
We multiply it with 28 to find the weight of 28 bricks.
The weight will be \[\dfrac{102}{17}\times 28=\dfrac{2856}{17}\] Kg.
For any fraction $ \dfrac{p}{q} $ , we first find the G.C.D of the denominator and the numerator. If it’s 1 then it’s already in its simplified form and if the G.C.D of the denominator and the numerator is any other number d then we need to divide the denominator and the numerator with d and get the simplified fraction form as $ \dfrac{{}^{p}/{}_{d}}{{}^{q}/{}_{d}} $ .
For our given fraction $ \dfrac{2856}{17} $ , the G.C.D of the denominator and the numerator is 17.
 $ \begin{align}
  & 17\left| \!{\underline {\,
  17,2856 \,}} \right. \\
 & 1\left| \!{\underline {\,
  1,168 \,}} \right. \\
\end{align} $
Now we divide both the denominator and the numerator with 17 and get $ \dfrac{{}^{2856}/{}_{17}}{{}^{17}/{}_{17}}=168 $ .
Therefore, the weight of 28 bricks is 168 Kg.
So, the correct answer is “168 Kg”.

Note: We can also convert it in the form of multiplication where we get the weight of 1 brick as $ \dfrac{102}{17}=6 $ Kg. Then we multiply with 28 to get $ 28\times 6=168 $ Kg as the solution.