How can I find the volume of $3\times {{10}^{25}}$ molecules of Neon gas at STP?
Answer
624.9k+ views
Hint: Mole, also pronounced as mol is a standard scientific unit used for measuring large quantities of very small entities such as atoms, molecules, or some other specified particles.
Complete answer:
Avogadro's number is the number of units present in per mole of any substance (defined as its molecular weight in grams), and is equal to the value $6\times {{10}^{23}}$. The units mentioned above may be electrons, atoms, ions, or molecules, depending on the nature of the substance and the character of the reaction (if any).
The value of the Avogadro constant was chosen such that the mass of one mole of a chemical compound, in grams, is numerically equal to the average mass of one molecule belonging to the compound, and is generally measured in daltons.
Atomic no is defined as the total no of protons present in the nucleus of an atom or total no of electrons present in the orbits surrounding the nucleus.
Mass number is defined as the total no of protons and neutrons present in the nucleus of an atom.
Volume is defined as the amount of space occupied by a substance, while mass is defined as the amount of matter that it contains. The amount of mass per unit of volume is called density.
S.I unit of volume is the meter cube.
Now the molar mass of Neon is 20g.
$6\times {{10}^{23}}$ molecules of Ne occupies 22.4 L
So, $3\times {{10}^{25}}$ molecules of Ne occupies $(\dfrac{3\times {{10}^{25}}}{6\times {{10}^{23}}})\times 22.4\,L$.
Note:
That long number is known as Avogadro's number after the first scientist Amadeo Avogadro in the nineteenth century. The mass of 1 mole of something in grams is the mass of that substance in mass units.
Complete answer:
Avogadro's number is the number of units present in per mole of any substance (defined as its molecular weight in grams), and is equal to the value $6\times {{10}^{23}}$. The units mentioned above may be electrons, atoms, ions, or molecules, depending on the nature of the substance and the character of the reaction (if any).
The value of the Avogadro constant was chosen such that the mass of one mole of a chemical compound, in grams, is numerically equal to the average mass of one molecule belonging to the compound, and is generally measured in daltons.
Atomic no is defined as the total no of protons present in the nucleus of an atom or total no of electrons present in the orbits surrounding the nucleus.
Mass number is defined as the total no of protons and neutrons present in the nucleus of an atom.
Volume is defined as the amount of space occupied by a substance, while mass is defined as the amount of matter that it contains. The amount of mass per unit of volume is called density.
S.I unit of volume is the meter cube.
Now the molar mass of Neon is 20g.
$6\times {{10}^{23}}$ molecules of Ne occupies 22.4 L
So, $3\times {{10}^{25}}$ molecules of Ne occupies $(\dfrac{3\times {{10}^{25}}}{6\times {{10}^{23}}})\times 22.4\,L$.
Note:
That long number is known as Avogadro's number after the first scientist Amadeo Avogadro in the nineteenth century. The mass of 1 mole of something in grams is the mass of that substance in mass units.
Recently Updated Pages
Which will be the least stable resonating structure class 11 chemistry CBSE

How many 5 digit telephone numbers can be construc-class-11-maths-CBSE

How do you find the angle of the resultant vector class 11 physics CBSE

Draw labelled diagram of the following i Gram seed class 11 biology CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

What is the need and importance of classification class 11 biology CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

10 examples of friction in our daily life

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference between physical and chemical change class 11 chemistry CBSE

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

