
Find the value of x if $ {\left( {150} \right)^{\text{x}}} = 7 $
$ \begin{align}
&A.\;\dfrac{{\log 7}}{{\log 3 + \log 5 + 1}} \\
&B.\;\dfrac{{\log 7}}{{\log 3 + \log 6}} \\
&C.\;\dfrac{{\log 7}}{{\log 3 + \log 5 + 10}} \\
&D.\;\dfrac{{\log 7}}{{\log 2 + \log 3}} \\
\end{align} $
Answer
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Hint:The various concepts and formulas related to logarithms will be used in this question. We can see that x is an exponent, so we will start by taking the logarithm of base 10 on both the sides. Then we will apply the formulas for logarithm that-
$ \begin{align}
&\log {a^x} = x\log a \\
&\log \left( {ab} \right) = \log a + \log b \\
&\log 10 = 1 \\
\end{align} $
Complete step-by-step answer:
We have to find the value of x in the equation $ {\left( {150} \right)^{\text{x}}} = 7 $ . So, we will first take logarithm of base 10 on both the sides which is-
$ \begin{align}
&{\left( {150} \right)^{\text{x}}} = 7 \\
&Taking\;\log \;on\;both\;sides, \\
&\log {\left( {150} \right)^{\text{x}}} = \log 7 \\
&Using\;the\;property\;log{a^{\text{x}}} = xloga, \\
&x\log\left( {150} \right) = \log 7 \\
\end{align} $
Now we will divide both the sides by log(150), which will bring the required value of x on one side of the equation as-
$ \begin{align}
&{\text{x}} = \dfrac{{\log 7}}{{\log 150}} \\
&We\;know\;that\;150 = 3 \times 5 \times 10 \\
&Using\;logab = loga + logb, \\
&\log 150 = \log \left( {3 \times 5 \times 10} \right) = \log 3 + \log 5 + \log 10 \\
&{\text{x}} = \dfrac{{\log 7}}{{\log 3 + \log 5 + \log 10}} \\
&We\;also\;know\;that\;\log 10 = 1,\; \\
&{\text{x}} = \dfrac{{\log 7}}{{\log 3 + \log 5 + 1}} \\
\end{align} $
This is the required value of x. Hence, the correct option is A.
Note: In such types of questions, it is important to take the correct base for the logarithm that we are taking on both the sides. Here, we took a base of 10 because of the requirement of the options. Also, we need to factorize 150 in such a way that it satisfies the option, because there can be various ways to factorize any number.
$ \begin{align}
&\log {a^x} = x\log a \\
&\log \left( {ab} \right) = \log a + \log b \\
&\log 10 = 1 \\
\end{align} $
Complete step-by-step answer:
We have to find the value of x in the equation $ {\left( {150} \right)^{\text{x}}} = 7 $ . So, we will first take logarithm of base 10 on both the sides which is-
$ \begin{align}
&{\left( {150} \right)^{\text{x}}} = 7 \\
&Taking\;\log \;on\;both\;sides, \\
&\log {\left( {150} \right)^{\text{x}}} = \log 7 \\
&Using\;the\;property\;log{a^{\text{x}}} = xloga, \\
&x\log\left( {150} \right) = \log 7 \\
\end{align} $
Now we will divide both the sides by log(150), which will bring the required value of x on one side of the equation as-
$ \begin{align}
&{\text{x}} = \dfrac{{\log 7}}{{\log 150}} \\
&We\;know\;that\;150 = 3 \times 5 \times 10 \\
&Using\;logab = loga + logb, \\
&\log 150 = \log \left( {3 \times 5 \times 10} \right) = \log 3 + \log 5 + \log 10 \\
&{\text{x}} = \dfrac{{\log 7}}{{\log 3 + \log 5 + \log 10}} \\
&We\;also\;know\;that\;\log 10 = 1,\; \\
&{\text{x}} = \dfrac{{\log 7}}{{\log 3 + \log 5 + 1}} \\
\end{align} $
This is the required value of x. Hence, the correct option is A.
Note: In such types of questions, it is important to take the correct base for the logarithm that we are taking on both the sides. Here, we took a base of 10 because of the requirement of the options. Also, we need to factorize 150 in such a way that it satisfies the option, because there can be various ways to factorize any number.
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