
Find the value of trigonometric equation ${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = ?
$
{\text{A}}{\text{. }}\dfrac{1}{2}{\text{cosec 38}}^\circ {\text{ sec 22}}^\circ \\
{\text{B}}{\text{. 2 sin 22}}^\circ {\text{ cos 38}}^\circ \\
{\text{C}}{\text{. - }}\dfrac{1}{2}{\text{cosec 22}}^\circ {\text{ sec 38}}^\circ \\
{\text{D}}{\text{. none of these}} \\
$
Answer
522.3k+ views
Hint: To solve the trigonometric equation given in the question we convert the tan and cot functions in terms of sin and cos functions and simplify using basic trigonometric identities for answer.
Complete step-by-step answer:
${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $\dfrac{{{\text{sin 38}}^\circ }}{{\cos 38^\circ }}$ - $\dfrac{{{\text{cos 22}}^\circ }}{{\sin 22^\circ }}$ -- (tanθ = $\dfrac{{\sin \theta }}{{\cos \theta }}$ and cotθ =$\dfrac{{\cos \theta }}{{\sin \theta }}$)
⟹${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $\dfrac{{{\text{sin 38}}^\circ {\text{sin 22}}^\circ - \cos {\text{ 22}}^\circ \cos {\text{ 38}}^\circ }}{{\cos 38^\circ {\text{sin 22}}^\circ }}$ --- (1)
We know that,
cos (A + B) = cos A cos B – sin A sin B
Using the above equation in equation (1), we get
⟹${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $\dfrac{{{\text{ - cos}}\left( {38 + 22} \right)^\circ }}{{\cos 38^\circ {\text{sin 22}}^\circ }}$
⟹${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $\dfrac{{{\text{ - cos}}\left( {60} \right)^\circ }}{{\cos 38^\circ {\text{sin 22}}^\circ }}$
⟹${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $\dfrac{{{\text{ - }}\dfrac{1}{2}}}{{\cos 38^\circ {\text{sin 22}}^\circ }}$
⟹${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $ - \dfrac{1}{2}{\text{cosec 22}}^\circ {\text{ sec 38}}^\circ $
Hence, Option C is the correct answer.
Note: In order to solve this type of questions the key is to convert the given trigonometric functions into a different form such that it can be simplified using a known trigonometric identity. Then we reduce it into another simple trigonometric value or a function using appropriate formulae, to determine the answer. Basic knowledge of trigonometric functions and identities is essential.
Complete step-by-step answer:
${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $\dfrac{{{\text{sin 38}}^\circ }}{{\cos 38^\circ }}$ - $\dfrac{{{\text{cos 22}}^\circ }}{{\sin 22^\circ }}$ -- (tanθ = $\dfrac{{\sin \theta }}{{\cos \theta }}$ and cotθ =$\dfrac{{\cos \theta }}{{\sin \theta }}$)
⟹${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $\dfrac{{{\text{sin 38}}^\circ {\text{sin 22}}^\circ - \cos {\text{ 22}}^\circ \cos {\text{ 38}}^\circ }}{{\cos 38^\circ {\text{sin 22}}^\circ }}$ --- (1)
We know that,
cos (A + B) = cos A cos B – sin A sin B
Using the above equation in equation (1), we get
⟹${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $\dfrac{{{\text{ - cos}}\left( {38 + 22} \right)^\circ }}{{\cos 38^\circ {\text{sin 22}}^\circ }}$
⟹${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $\dfrac{{{\text{ - cos}}\left( {60} \right)^\circ }}{{\cos 38^\circ {\text{sin 22}}^\circ }}$
⟹${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $\dfrac{{{\text{ - }}\dfrac{1}{2}}}{{\cos 38^\circ {\text{sin 22}}^\circ }}$
⟹${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $ - \dfrac{1}{2}{\text{cosec 22}}^\circ {\text{ sec 38}}^\circ $
Hence, Option C is the correct answer.
Note: In order to solve this type of questions the key is to convert the given trigonometric functions into a different form such that it can be simplified using a known trigonometric identity. Then we reduce it into another simple trigonometric value or a function using appropriate formulae, to determine the answer. Basic knowledge of trigonometric functions and identities is essential.
Recently Updated Pages
The correct geometry and hybridization for XeF4 are class 11 chemistry CBSE

Water softening by Clarks process uses ACalcium bicarbonate class 11 chemistry CBSE

With reference to graphite and diamond which of the class 11 chemistry CBSE

A certain household has consumed 250 units of energy class 11 physics CBSE

The lightest metal known is A beryllium B lithium C class 11 chemistry CBSE

What is the formula mass of the iodine molecule class 11 chemistry CBSE

Trending doubts
Is Cellular respiration an Oxidation or Reduction class 11 chemistry CBSE

In electron dot structure the valence shell electrons class 11 chemistry CBSE

What is the Pitti Island famous for ABird Sanctuary class 11 social science CBSE

State the laws of reflection of light

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells
