
Find the value of trigonometric equation ${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = ?
$
{\text{A}}{\text{. }}\dfrac{1}{2}{\text{cosec 38}}^\circ {\text{ sec 22}}^\circ \\
{\text{B}}{\text{. 2 sin 22}}^\circ {\text{ cos 38}}^\circ \\
{\text{C}}{\text{. - }}\dfrac{1}{2}{\text{cosec 22}}^\circ {\text{ sec 38}}^\circ \\
{\text{D}}{\text{. none of these}} \\
$
Answer
618.6k+ views
Hint: To solve the trigonometric equation given in the question we convert the tan and cot functions in terms of sin and cos functions and simplify using basic trigonometric identities for answer.
Complete step-by-step answer:
${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $\dfrac{{{\text{sin 38}}^\circ }}{{\cos 38^\circ }}$ - $\dfrac{{{\text{cos 22}}^\circ }}{{\sin 22^\circ }}$ -- (tanθ = $\dfrac{{\sin \theta }}{{\cos \theta }}$ and cotθ =$\dfrac{{\cos \theta }}{{\sin \theta }}$)
⟹${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $\dfrac{{{\text{sin 38}}^\circ {\text{sin 22}}^\circ - \cos {\text{ 22}}^\circ \cos {\text{ 38}}^\circ }}{{\cos 38^\circ {\text{sin 22}}^\circ }}$ --- (1)
We know that,
cos (A + B) = cos A cos B – sin A sin B
Using the above equation in equation (1), we get
⟹${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $\dfrac{{{\text{ - cos}}\left( {38 + 22} \right)^\circ }}{{\cos 38^\circ {\text{sin 22}}^\circ }}$
⟹${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $\dfrac{{{\text{ - cos}}\left( {60} \right)^\circ }}{{\cos 38^\circ {\text{sin 22}}^\circ }}$
⟹${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $\dfrac{{{\text{ - }}\dfrac{1}{2}}}{{\cos 38^\circ {\text{sin 22}}^\circ }}$
⟹${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $ - \dfrac{1}{2}{\text{cosec 22}}^\circ {\text{ sec 38}}^\circ $
Hence, Option C is the correct answer.
Note: In order to solve this type of questions the key is to convert the given trigonometric functions into a different form such that it can be simplified using a known trigonometric identity. Then we reduce it into another simple trigonometric value or a function using appropriate formulae, to determine the answer. Basic knowledge of trigonometric functions and identities is essential.
Complete step-by-step answer:
${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $\dfrac{{{\text{sin 38}}^\circ }}{{\cos 38^\circ }}$ - $\dfrac{{{\text{cos 22}}^\circ }}{{\sin 22^\circ }}$ -- (tanθ = $\dfrac{{\sin \theta }}{{\cos \theta }}$ and cotθ =$\dfrac{{\cos \theta }}{{\sin \theta }}$)
⟹${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $\dfrac{{{\text{sin 38}}^\circ {\text{sin 22}}^\circ - \cos {\text{ 22}}^\circ \cos {\text{ 38}}^\circ }}{{\cos 38^\circ {\text{sin 22}}^\circ }}$ --- (1)
We know that,
cos (A + B) = cos A cos B – sin A sin B
Using the above equation in equation (1), we get
⟹${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $\dfrac{{{\text{ - cos}}\left( {38 + 22} \right)^\circ }}{{\cos 38^\circ {\text{sin 22}}^\circ }}$
⟹${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $\dfrac{{{\text{ - cos}}\left( {60} \right)^\circ }}{{\cos 38^\circ {\text{sin 22}}^\circ }}$
⟹${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $\dfrac{{{\text{ - }}\dfrac{1}{2}}}{{\cos 38^\circ {\text{sin 22}}^\circ }}$
⟹${\text{tan38}}^\circ - {\text{cot22}}^\circ $ = $ - \dfrac{1}{2}{\text{cosec 22}}^\circ {\text{ sec 38}}^\circ $
Hence, Option C is the correct answer.
Note: In order to solve this type of questions the key is to convert the given trigonometric functions into a different form such that it can be simplified using a known trigonometric identity. Then we reduce it into another simple trigonometric value or a function using appropriate formulae, to determine the answer. Basic knowledge of trigonometric functions and identities is essential.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

