Question

Find the value of the equation given ${( - 6)^2} \times {( - 6)^4} \times {( - 6)^3} = ?$

Answer 1

Hint – In order to solve this problem we need to know that the square of any negative number is positive, the cube of any negative number is negative and any negative number raised to the power 4 is also positive. Knowing this will solve your problem.

Complete step-by-step answer:
The given equation is ${( - 6)^2} \times {( - 6)^4} \times {( - 6)^3}$
As we know ${( - a)^2} = {a^2},\,{( - b)^3} = - {b^3},\,{( - c)^4} = {c^4}$
So, we can say ${( - 6)^2} = 36,\,{( - 6)^3} = - 216,\,{( - 6)^4} = 1296$
Putting these values in the given equation we get the value of equation as:-
${( - 6)^2} \times {( - 6)^4} \times {( - 6)^3}$= $36 \times ( - 216) \times (1296) = - 10077696$
Hence, the value of the given equation is -10077696.

Note – When you face such types of problems then you just need to know the multiplication of numbers and square of any negative number is positive, cube of any negative number is negative and any negative number raised to the power 4 is also positive. Knowing this will solve your problem.