Find the value of $\tan 300^\circ $
Answer
576.6k+ views
Hint:We are given a trigonometric function of tangent with an angle of $300$ degrees and we have to find its value. For this we use the Cartesian plane for trigonometric functions’ sine i.e. positive or negative and use the standard table of trigonometric functions value at particular angles.
Complete solution step by step:
Firstly we write down the expression of which we are supposed to find the value
$\tan 300^\circ $
We are given a tangent function whose argument is provided as 300 degrees now we have to see that in which quadrant it lies so that we can get which sign it will take after converting it into standard degree angles whose values are known to us for all six functions. We understand this by the below simplification and given figure (a) i.e.
$\tan 300^\circ = \tan \left( {360^\circ - 60^\circ } \right)$
We can see that it lies in the fourth quadrant. Now we look at the figure and conclude which sign it will take with it after conversion i.e.
We can clearly see that tangent is positive in third quadrant and first quadrant and it will be negative in the fourth quadrant so we have
$\tan 300^\circ = \tan \left( {360^\circ - 60^\circ } \right) = - \tan 60^\circ $
We have simplified the value of tangent into standard angle value. Now looking this value up in the below table
We have
$ - \tan 60^\circ = - \sqrt 3 $
This is the final outcome of the given tangent function.
Note: Wherever possible conversion of trigonometric functions should be done with respect to either $180^\circ $ or$0^\circ ,360^\circ $ for simpler calculations. Because this conversion does not lead to conversion of function such as sine converts into cosine which happens while doing so with $90^\circ \,{\text{or}}\,270^\circ $.
Complete solution step by step:
Firstly we write down the expression of which we are supposed to find the value
$\tan 300^\circ $
We are given a tangent function whose argument is provided as 300 degrees now we have to see that in which quadrant it lies so that we can get which sign it will take after converting it into standard degree angles whose values are known to us for all six functions. We understand this by the below simplification and given figure (a) i.e.
$\tan 300^\circ = \tan \left( {360^\circ - 60^\circ } \right)$
We can see that it lies in the fourth quadrant. Now we look at the figure and conclude which sign it will take with it after conversion i.e.
We can clearly see that tangent is positive in third quadrant and first quadrant and it will be negative in the fourth quadrant so we have
$\tan 300^\circ = \tan \left( {360^\circ - 60^\circ } \right) = - \tan 60^\circ $
We have simplified the value of tangent into standard angle value. Now looking this value up in the below table
We have
$ - \tan 60^\circ = - \sqrt 3 $
This is the final outcome of the given tangent function.
Note: Wherever possible conversion of trigonometric functions should be done with respect to either $180^\circ $ or$0^\circ ,360^\circ $ for simpler calculations. Because this conversion does not lead to conversion of function such as sine converts into cosine which happens while doing so with $90^\circ \,{\text{or}}\,270^\circ $.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

