How do I find the value of sec 5pi/6 ?
Answer
579.9k+ views
Hint: Convert the angle to the required form to apply the ASTC rule. Express sec in terms of cos by taking the reciprocal. Then put the cos value of the angle and do the necessary calculation to obtain the required solution.
Complete step by step solution:
ASTC rule: we have different trigonometric functions like sin, cos, tan etc. ASTC stands for all, sin, tan, cos. This rule indicates the positivity of a particular trigonometric function on a particular quadrant as per the following table. For even multipliers of angle $\dfrac{\pi }{2}$ , the function remains the same. But for an odd multiplier of angle $\dfrac{\pi }{2}$ the values change accordingly.
We have, \[\sec \dfrac{5\pi }{6}\]
\[\sec \dfrac{5\pi }{6}\] can be written as \[\sec \dfrac{5\pi }{6}=\sec \left( \dfrac{\pi }{2}\times 2-\dfrac{\pi }{6} \right)\]
Since the angle is even multiplier of angle $\dfrac{\pi }{2}$, so the function remains the same i.e. sec.
And the angle lies in the ${{2}^{nd}}$ quadrant (as each quadrant is consists of $\dfrac{\pi }{2}$).
From the above table we can conclude that sec is a negative function in the ${{2}^{nd}}$ quadrant.
Now, our angle becomes
\[\sec \dfrac{5\pi }{6}=-\sec \dfrac{\pi }{6}\]
As we know, $\sec \theta =\dfrac{1}{\cos \theta }$
So, \[\sec \dfrac{\pi }{6}\] can be written as \[\sec \dfrac{\pi }{6}=\dfrac{1}{\cos \dfrac{\pi }{6}}\]
Putting the value of \[\sec \dfrac{\pi }{6}\], we get
\[\sec \dfrac{5\pi }{6}=-\dfrac{1}{\cos \dfrac{\pi }{6}}\]
Again as we know \[\cos \dfrac{\pi }{6}=\dfrac{\sqrt{3}}{2}\]
Putting the value of \[\cos \dfrac{\pi }{6}\], we get
\[\sec \dfrac{5\pi }{6}=-\dfrac{1}{\dfrac{\sqrt{3}}{2}}=-1\times \dfrac{2}{\sqrt{3}}=-\dfrac{2}{\sqrt{3}}\]
Multiplying the numerator and the denominator with $\sqrt{3}$ we get
\[\sec \dfrac{5\pi }{6}=-\dfrac{2\times \sqrt{3}}{\sqrt{3}\times \sqrt{3}}=-\dfrac{2\sqrt{3}}{3}\]
This is the required solution.
Note: Converting to the required form is the most important step, to which ASTC rule will be applicable. Some basic sin and cos angle values should be remembered for faster calculations.
Complete step by step solution:
ASTC rule: we have different trigonometric functions like sin, cos, tan etc. ASTC stands for all, sin, tan, cos. This rule indicates the positivity of a particular trigonometric function on a particular quadrant as per the following table. For even multipliers of angle $\dfrac{\pi }{2}$ , the function remains the same. But for an odd multiplier of angle $\dfrac{\pi }{2}$ the values change accordingly.
| Quadrant | Positive function |
| ${{1}^{st}}$ | All |
| ${{2}^{nd}}$ | sin and cosec |
| ${{3}^{rd}}$ | tan and cot |
| ${{4}^{th}}$ | cos and sec |
We have, \[\sec \dfrac{5\pi }{6}\]
\[\sec \dfrac{5\pi }{6}\] can be written as \[\sec \dfrac{5\pi }{6}=\sec \left( \dfrac{\pi }{2}\times 2-\dfrac{\pi }{6} \right)\]
Since the angle is even multiplier of angle $\dfrac{\pi }{2}$, so the function remains the same i.e. sec.
And the angle lies in the ${{2}^{nd}}$ quadrant (as each quadrant is consists of $\dfrac{\pi }{2}$).
From the above table we can conclude that sec is a negative function in the ${{2}^{nd}}$ quadrant.
Now, our angle becomes
\[\sec \dfrac{5\pi }{6}=-\sec \dfrac{\pi }{6}\]
As we know, $\sec \theta =\dfrac{1}{\cos \theta }$
So, \[\sec \dfrac{\pi }{6}\] can be written as \[\sec \dfrac{\pi }{6}=\dfrac{1}{\cos \dfrac{\pi }{6}}\]
Putting the value of \[\sec \dfrac{\pi }{6}\], we get
\[\sec \dfrac{5\pi }{6}=-\dfrac{1}{\cos \dfrac{\pi }{6}}\]
Again as we know \[\cos \dfrac{\pi }{6}=\dfrac{\sqrt{3}}{2}\]
Putting the value of \[\cos \dfrac{\pi }{6}\], we get
\[\sec \dfrac{5\pi }{6}=-\dfrac{1}{\dfrac{\sqrt{3}}{2}}=-1\times \dfrac{2}{\sqrt{3}}=-\dfrac{2}{\sqrt{3}}\]
Multiplying the numerator and the denominator with $\sqrt{3}$ we get
\[\sec \dfrac{5\pi }{6}=-\dfrac{2\times \sqrt{3}}{\sqrt{3}\times \sqrt{3}}=-\dfrac{2\sqrt{3}}{3}\]
This is the required solution.
Note: Converting to the required form is the most important step, to which ASTC rule will be applicable. Some basic sin and cos angle values should be remembered for faster calculations.
Recently Updated Pages
Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Class 10 Question and Answer - Your Ultimate Solutions Guide

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Trending doubts
What is the full form of NDA a National Democratic class 10 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

Who Won 36 Oscar Awards? Record Holder Revealed

Bharatiya Janata Party was founded in the year A 1979 class 10 social science CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

Why is it 530 pm in india when it is 1200 afternoon class 10 social science CBSE

