
Find the value of k for which the following system of equations has no solution:
$3x-4y+7=0$ and $kx+3y-5=0$.
Answer
626.1k+ views
Hint: In this problem, we will the condition for which a system of linear equations has no solution which is given as $\dfrac{{{a}_{1}}}{{{a}_{2}}}=\dfrac{{{b}_{1}}}{{{b}_{2}}}\ne \dfrac{{{c}_{1}}}{{{c}_{2}}}$ . After applying this condition to the given system of linear equations, we can find the value of k.
Complete Step-by-Step solution:
A system of linear equations can have no solution, a unique solution or infinitely many solutions. A given system of linear equations has no solution if the equations are inconsistent.
If a system of linear equation is given as:
$\begin{align}
& {{a}_{1}}x+{{b}_{1}}y+{{c}_{1}}=0 \\
& {{a}_{2}}x+{{b}_{2}}y+{{c}_{2}}=0 \\
\end{align}$
For the above system of linear equations to be inconsistent, it must satisfy the condition that:
$\dfrac{{{a}_{1}}}{{{a}_{2}}}=\dfrac{{{b}_{1}}}{{{b}_{2}}}\ne \dfrac{{{c}_{1}}}{{{c}_{2}}}$ , that is the graph of the equations must be parallel to each other.
For the system of linear equations to have infinite solutions, it must satisfy the condition that $\dfrac{{{a}_{1}}}{{{a}_{2}}}=\dfrac{{{b}_{1}}}{{{b}_{2}}}=\dfrac{{{c}_{1}}}{{{c}_{2}}}$, that is the graph of the equations must coincide.
For the system of linear equations to have a unique solution:
$\dfrac{{{a}_{1}}}{{{a}_{2}}}\ne \dfrac{{{b}_{1}}}{{{b}_{2}}}\ne \dfrac{{{c}_{1}}}{{{c}_{2}}}$
Now, the system of linear equations given to us is:
$\begin{align}
& 3x-4y+7=0 \\
& kx+3y-5=0 \\
\end{align}$
For this given system of equations to have no solution, it should satisfy:
$\dfrac{3}{k}=\dfrac{-4}{3}\ne \dfrac{7}{-5}$
So, we have:
$\begin{align}
& \dfrac{3}{k}=\dfrac{-4}{3} \\
& \Rightarrow 9=-4k \\
& \Rightarrow k=\dfrac{-9}{4} \\
\end{align}$
Also, we have:
$\begin{align}
& \dfrac{3}{k}\ne \dfrac{-7}{5} \\
& \Rightarrow 15\ne -7k \\
& \Rightarrow k\ne \dfrac{-15}{7} \\
\end{align}$
Hence, the value of k is equal to $\dfrac{-9}{4}$ given equation will have no solution.
Note: Students should note here that for a system of linear equations to be inconsistent, the graph of the equations must be parallel to each other. So, the ratio of coefficients of x and y must be equal and it should not be equal to the ratio of the constant term.
Complete Step-by-Step solution:
A system of linear equations can have no solution, a unique solution or infinitely many solutions. A given system of linear equations has no solution if the equations are inconsistent.
If a system of linear equation is given as:
$\begin{align}
& {{a}_{1}}x+{{b}_{1}}y+{{c}_{1}}=0 \\
& {{a}_{2}}x+{{b}_{2}}y+{{c}_{2}}=0 \\
\end{align}$
For the above system of linear equations to be inconsistent, it must satisfy the condition that:
$\dfrac{{{a}_{1}}}{{{a}_{2}}}=\dfrac{{{b}_{1}}}{{{b}_{2}}}\ne \dfrac{{{c}_{1}}}{{{c}_{2}}}$ , that is the graph of the equations must be parallel to each other.
For the system of linear equations to have infinite solutions, it must satisfy the condition that $\dfrac{{{a}_{1}}}{{{a}_{2}}}=\dfrac{{{b}_{1}}}{{{b}_{2}}}=\dfrac{{{c}_{1}}}{{{c}_{2}}}$, that is the graph of the equations must coincide.
For the system of linear equations to have a unique solution:
$\dfrac{{{a}_{1}}}{{{a}_{2}}}\ne \dfrac{{{b}_{1}}}{{{b}_{2}}}\ne \dfrac{{{c}_{1}}}{{{c}_{2}}}$
Now, the system of linear equations given to us is:
$\begin{align}
& 3x-4y+7=0 \\
& kx+3y-5=0 \\
\end{align}$
For this given system of equations to have no solution, it should satisfy:
$\dfrac{3}{k}=\dfrac{-4}{3}\ne \dfrac{7}{-5}$
So, we have:
$\begin{align}
& \dfrac{3}{k}=\dfrac{-4}{3} \\
& \Rightarrow 9=-4k \\
& \Rightarrow k=\dfrac{-9}{4} \\
\end{align}$
Also, we have:
$\begin{align}
& \dfrac{3}{k}\ne \dfrac{-7}{5} \\
& \Rightarrow 15\ne -7k \\
& \Rightarrow k\ne \dfrac{-15}{7} \\
\end{align}$
Hence, the value of k is equal to $\dfrac{-9}{4}$ given equation will have no solution.
Note: Students should note here that for a system of linear equations to be inconsistent, the graph of the equations must be parallel to each other. So, the ratio of coefficients of x and y must be equal and it should not be equal to the ratio of the constant term.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Class 10 Question and Answer - Your Ultimate Solutions Guide

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Trending doubts
Which country won the ICC Men's ODI World Cup in 2023?

In cricket, how many legal balls are there in a standard over?

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A boat goes 24 km upstream and 28 km downstream in class 10 maths CBSE

What does "powerplay" mean in limited-overs cricket?

What is the "Powerplay" in T20 cricket?

