Find the value of $\cos \dfrac{\pi }{8}$.
A) $\sqrt{\dfrac{\sqrt{2}-1}{2\sqrt{2}}}$
B) $\sqrt{\dfrac{\sqrt{2}+1}{2\sqrt{2}}}$
C) $\sqrt{\dfrac{\sqrt{2}+1}{2\sqrt{3}}}$
D) $\sqrt{\dfrac{\sqrt{2}+1}{\sqrt{2}}}$
Answer
647.1k+ views
Hint: In this question, we have to bring the given expression in the form of the cosine of a standard angle, whose cosine value is known. Thereafter, we can obtain the value of the given expression in terms of the cosine value of the standard angle (which is ${{45}^{\circ }}$ in this case).
Complete step-by-step answer:
In this case, the expression to be evaluated is $\cos \dfrac{\pi }{8}$. We should try to bring it in terms of the trigonometric ratios of one of the standard angles i.e. $\dfrac{\pi }{2},\dfrac{\pi }{3},\dfrac{\pi }{4},\dfrac{\pi }{6}$ whose trigonometric ratios are known. In this case, we notice that $\dfrac{\pi }{8}$ can be written as $\dfrac{\pi }{8}=\dfrac{\pi }{2\times 4}=\dfrac{1}{2}\times \dfrac{\pi }{4}$.
We can now use the cosine of sum of angles rule
\[\cos (x+y)=\cos (x)\cos (y)-\sin (x)\sin (y)\]
We can take y=x in the above formula which gives the cosine of twice an angle x as
$\begin{align}
& \cos (2x)={{\cos }^{2}}(x)-{{\sin }^{2}}(x)={{\cos }^{2}}(x)-(1-{{\cos }^{2}}x)=2{{\cos }^{2}}x-1 \\
& \Rightarrow \cos (x)=\sqrt{\dfrac{1+\cos (2x)}{2}}..................................(1.1) \\
\end{align}$
Thus, in this case we can take $x=\dfrac{\pi }{8}$. Then, $2x=\dfrac{\pi }{4}$, using these values in equation(1.1), we obtain
\[\cos (\dfrac{\pi }{8})=\sqrt{\dfrac{1+\cos \left( \dfrac{\pi }{4} \right)}{2}}.......................(1.2)\]
Now, we also know that \[\cos \left( \dfrac{\pi }{4} \right)=\cos ({{45}^{\circ }})=\dfrac{1}{\sqrt{2}}\]. Using these values in equation (1.2), we get
\[\cos (\dfrac{\pi }{8})=\sqrt{\dfrac{1+\cos \left( {{45}^{\circ }} \right)}{2}}=\sqrt{\dfrac{1+\dfrac{1}{\sqrt{2}}}{2}}=\sqrt{\dfrac{\sqrt{2}+1}{2\sqrt{2}}}\]
Therefore, the answer to this question should be option(B).
Note: In this case we should be careful to use the cosine of twice an angle formula because there are three formulas for cos of twice an angle and note that there should be an overall square root in the answer.
Complete step-by-step answer:
In this case, the expression to be evaluated is $\cos \dfrac{\pi }{8}$. We should try to bring it in terms of the trigonometric ratios of one of the standard angles i.e. $\dfrac{\pi }{2},\dfrac{\pi }{3},\dfrac{\pi }{4},\dfrac{\pi }{6}$ whose trigonometric ratios are known. In this case, we notice that $\dfrac{\pi }{8}$ can be written as $\dfrac{\pi }{8}=\dfrac{\pi }{2\times 4}=\dfrac{1}{2}\times \dfrac{\pi }{4}$.
We can now use the cosine of sum of angles rule
\[\cos (x+y)=\cos (x)\cos (y)-\sin (x)\sin (y)\]
We can take y=x in the above formula which gives the cosine of twice an angle x as
$\begin{align}
& \cos (2x)={{\cos }^{2}}(x)-{{\sin }^{2}}(x)={{\cos }^{2}}(x)-(1-{{\cos }^{2}}x)=2{{\cos }^{2}}x-1 \\
& \Rightarrow \cos (x)=\sqrt{\dfrac{1+\cos (2x)}{2}}..................................(1.1) \\
\end{align}$
Thus, in this case we can take $x=\dfrac{\pi }{8}$. Then, $2x=\dfrac{\pi }{4}$, using these values in equation(1.1), we obtain
\[\cos (\dfrac{\pi }{8})=\sqrt{\dfrac{1+\cos \left( \dfrac{\pi }{4} \right)}{2}}.......................(1.2)\]
Now, we also know that \[\cos \left( \dfrac{\pi }{4} \right)=\cos ({{45}^{\circ }})=\dfrac{1}{\sqrt{2}}\]. Using these values in equation (1.2), we get
\[\cos (\dfrac{\pi }{8})=\sqrt{\dfrac{1+\cos \left( {{45}^{\circ }} \right)}{2}}=\sqrt{\dfrac{1+\dfrac{1}{\sqrt{2}}}{2}}=\sqrt{\dfrac{\sqrt{2}+1}{2\sqrt{2}}}\]
Therefore, the answer to this question should be option(B).
Note: In this case we should be careful to use the cosine of twice an angle formula because there are three formulas for cos of twice an angle and note that there should be an overall square root in the answer.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Two of the body parts which do not appear in MRI are class 11 biology CBSE

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

