
Find the value of $1\text{ + 222 }\div \text{ 20 + 4444 }\div \text{ 400}$.
Answer
626.1k+ views
Hint: Obey the BODMAS rule, where division comes before addition. Thus, perform the two divisions first, then add up the quantities to get the final answer. BODMAS means Bracket, Of, Division, Multiplication, Addition and Subtraction in that order. Hence, here we first follow the method of division before we perform addition.
Complete step-by-step answer:
Now, we simplify the given problem as,
$\begin{align}
& 1\text{ + 222 }\div \text{ 20 + 4444 }\div \text{ 400} \\
& =\text{ 1 + }\dfrac{222}{20}\text{ + }\dfrac{4444}{400} \\
& =\text{ 1 + 11}\text{.1 + 11}\text{.11} \\
& \text{= 13}\text{.21} \\
\end{align}$
Thus, the correct answer is 13.21
Note: If the BODMAS rule isn’t followed and we go from left to right simplifying it, then it will give a wrong answer.If we had done the simplification problem without following BODMAS rule and did it from left to right, then we would get,
$\begin{align}
& 1\text{ + 222 }\div \text{ 20 + 4444 }\div \text{ 400} \\
& =\text{ 223 }\div \text{ 20 + 4444 }\div \text{ 400} \\
& =\text{ }\dfrac{223}{20}\text{ + 4444 }\div \text{ 400} \\
& \text{= 11}\text{.15 + 4444 }\div \text{ 400} \\
& =\text{ 4455}\text{.15 }\div \text{ 400} \\
& =\text{ 11}\text{.137875} \\
\end{align}$
This is not the correct answer. Thus, we must follow the BODMAS rule.
Complete step-by-step answer:
Now, we simplify the given problem as,
$\begin{align}
& 1\text{ + 222 }\div \text{ 20 + 4444 }\div \text{ 400} \\
& =\text{ 1 + }\dfrac{222}{20}\text{ + }\dfrac{4444}{400} \\
& =\text{ 1 + 11}\text{.1 + 11}\text{.11} \\
& \text{= 13}\text{.21} \\
\end{align}$
Thus, the correct answer is 13.21
Note: If the BODMAS rule isn’t followed and we go from left to right simplifying it, then it will give a wrong answer.If we had done the simplification problem without following BODMAS rule and did it from left to right, then we would get,
$\begin{align}
& 1\text{ + 222 }\div \text{ 20 + 4444 }\div \text{ 400} \\
& =\text{ 223 }\div \text{ 20 + 4444 }\div \text{ 400} \\
& =\text{ }\dfrac{223}{20}\text{ + 4444 }\div \text{ 400} \\
& \text{= 11}\text{.15 + 4444 }\div \text{ 400} \\
& =\text{ 4455}\text{.15 }\div \text{ 400} \\
& =\text{ 11}\text{.137875} \\
\end{align}$
This is not the correct answer. Thus, we must follow the BODMAS rule.
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